Question

i具有查看对象质量并将新属性推入新属性的功能。我想将当前对象的级别保存为新对象的属性。（数据[0]，数据[1]，..-级别1 数据[0] .childs [0]，数据[1] .childs [0]，..-level2 ... ）
但是我的代码中有两个交叉链接的函数，我为此大吃一惊。

 var data = [
	{a1: 1, a2: 2, childs: [{a1: 12, a2: 13, childs: [{a1: "test114", childs:[]}]}, {a1: 114, a2: 115, childs: [{a1:1116, a2: 1117, childs: []}]}] },
	{a1: 3, a2: 4, childs: [{a1: 22, a2: 23, childs: []}, {a1: 224, a2: 223, childs: [{a1:2221, a2: 2222, childs: []}]}] },
	{a1: 5, a2: 6, childs: [{a1: 32, a2: 33, childs: []}] },
	{a1: 7, a2: 8, childs: []}
 ];


var mass = [];
var newarray = [];
var level = 1;



function go() {
	returnObject(data, mass);
  console.log(mass);
}

function returnObject(obj, arr) {

	
	obj.forEach(function(item) {
	  returnObject2(item, arr);
	});
}

function returnObject2(obj, arr){
		console.log(obj);
		console.log(arr)

		if(Array.isArray(obj)){
			return
		}

		if (obj.childs.length > 0){

			arr.push({new:obj.a1, childs: obj.childs, level: level});
			level+=1;
			return returnObject(obj.childs, arr);
		}
		else {
			return arr.push({new:obj.a1, childs: [], level: level});
		}
}

<button onClick=go()> go!</button>

Answer 1

不要将level设置为全局变量，将其传递出去！

function returnObject(obj, arr, level) {
    obj.forEach(function(item) {
      returnObject2(item, arr, level + 1);
    });
}

function returnObject2(obj, arr, level){
   ...
   return returnObject(obj.childs, arr, level + 1);

etc

在交叉链接的函数中保存嵌套级别

1 个答案: