在null上调用成员函数View()

时间:2018-10-11 06:12:17

标签: php smarty

此方法中的我的IF转发到查看变量$this->session['stCeneo']

public function onCheckoutPostDispatch(\Enlight_Event_EventArgs $args)
    {
        $this->subject = $args->getSubject();


   if ('finish' === $this->subject->Request()->getActionName()) {
            $this->saveRequestToSession();

            $view = $subject->View(); //error?
            $view->assign('stCeneo', $this->session['stCeneo']); //error?

        }

$this->session['stCeneo']saveRequestToSession()中实现。

private function saveRequestToSession()
{
    if ($this->subject->Request()->getParam('stOpineo') !== null) {
        $this->session['stOpineo'] = $this->subject->Request()->getParam('stOpineo') ? true : false;
    }

    if ($this->subject->Request()->getParam('stCeneo') !== null) {
        $this->session['stCeneo'] = $this->subject->Request()->getParam('stCeneo') ? true : false;
    }
}

所以我不知道,为什么我的行中有错误注释:

  

未捕获的错误:调用成员函数View()为空

1 个答案:

答案 0 :(得分:0)

好的,我解决了这个问题。我写道:

$this->subject->View()->assign('stCeneo', $this->session['stCeneo']);