Question

我正在尝试使用此处描述的标准iOS集成创建费用：https://stripe.com/docs/mobile/ios/standard

要做到这一点，我在CheckoutController.swift中

func paymentContext(_ paymentContext: STPPaymentContext, didCreatePaymentResult paymentResult: STPPaymentResult, completion: @escaping STPErrorBlock) {

    StripeClient.shared.completeCharge(paymentResult, amount: 1000, shippingAddress: nil, shippingMethod: nil, completion: { (error: Error?) in
        if let error = error {
            completion(error)
        } else {
            completion(nil)
        }
    })
}

在我的StripeClient.swift中

func completeCharge(_ result: STPPaymentResult,
                    amount: Int,
                    shippingAddress: STPAddress?,
                    shippingMethod: PKShippingMethod?,
                    completion: @escaping STPErrorBlock) {
    let url = self.baseURL.appendingPathComponent("charge")

    var params: [String: Any] = [
        "source": result.source.stripeID,
        "amount": amount,
        "description": Purchase.shared.description()
    ]
    params["shipping"] = STPAddress.shippingInfoForCharge(with: shippingAddress, shippingMethod: shippingMethod)
    Alamofire.request(url, method: .post, parameters: params, headers: Credentials.headersDictionary())
        .validate(statusCode: 200..<300)
        .responseString { response in
            switch response.result {
            case .success:
                completion(nil)
            case .failure(let error):
                completion(error)
            }
    }
}

而且，在我的API（Ruby on Rails）中

  def charge
    Stripe::Charge.create(charge_params)
    render json: { success: true }, status: :ok
  rescue Stripe::StripeError => e
    render json: { error: "Error creating charge: #{e.message}" },
           status: :payment_required
  end

  private

  def charge_params
    params
      .permit(:amount, :description, :source)
      .merge(currency: 'gbp')
  end

问题出在completeCharge方法中，result.source.stripeID返回卡ID（card_xxxxxx），但我需要令牌（tok_xxxxxx）。所以，

如何从卡ID或STPPaymentResult对象获取令牌？或如何让我的Rails API使用卡ID代替令牌？或任何其他解决方案？

致谢。

Answer 1

去！当您使用card_id代替令牌时，有必要将客户ID作为参数传递，因此，我修改了api：

  def charge_params
    params
      .permit(:amount, :description, :source)
      .merge(currency: 'gbp',
             customer: current_user.stripe_customer_id)
  end

（我将Stripe客户ID作为stripe_customer_id存储在我的用户表中）

Stripe iOS：我无法使用卡ID进行收费

1 个答案: