Question

我对代码非常陌生，当我尝试创建带有比较字符的if / else语句时遇到了一个问题。在我尝试编写的代码中，用户正在“赌博”他们是否认为骰子掷骰高于7，低于7或恰好是7。我已经附加了为获取方法编写的代码他们的猜测。当我输入'h'，'H'，'l'或'L'时，我收到错误消息，但是当我输入'S'或's'时，该方法可以正常工作。知道为什么吗？预先感谢！

    private static char getHighLow(Scanner inScanner) {
    System.our.print("High, low or sevens (H/L/S): ");
    String str = in.Scanner.nextLine();
    char highLow = str.charAt(0);
    char highOne = 'h'; char highTwo = 'H'; char lowOne = 'l'; char lowTwo = 'L'; char sevenOne = 's'; char sevenTwo = 'S';
    if ((highLow == highOne) | (highLow == highTwo)) {
        highLow = 'h';
    }  
    if ((highLow == lowOne) | (highLow == lowTwo)) {
        highLow = 'l';
    if ((highLow == sevenOne) | (highLow == sevenTwo)) {
        highLow = 's';
    }
    else {
        System.out.println("ERROR- enter h, l, or s");
        System.out.print("High, low, or sevens (H/L/S): ");
        str = in.Scanner.nextLine();
        highLow = str.charAt(0);
    }
    return highLow;
    }

Answer 1

您需要正确放置else块。更好地使用else if：

    if ((highLow == highOne) | (highLow == highTwo)) {
        highLow = 'h';
    } else if ((highLow == lowOne) | (highLow == lowTwo)) {
        highLow = 'l';
    } else if ((highLow == sevenOne) | (highLow == sevenTwo)) {
        highLow = 's';
    } else {
        System.out.println("ERROR- enter h, l, or s");
        System.out.print("High, low, or sevens (H/L/S): ");
        str = inScanner.nextLine();
        highLow = str.charAt(0);
    }

您也可以使用开关盒以提高可读性。

比较Java中的字符？

1 个答案: