Question

我想更新tableview菜单项控制器中的菜单项，因为现在我只能获取这些菜单项

我已经实现了：

func tableView(_ tableView: UITableView, shouldShowMenuForRowAt indexPath: IndexPath) -> Bool {
        let forword = UIMenuItem(title: "Demo", action: #selector(self.demo))
        UIMenuController.shared.menuItems?.append(forword)
        UIMenuController.shared.update()
        return true
    }

    func tableView(_ tableView: UITableView, performAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) {
        UIMenuController.shared.setMenuVisible(true, animated: true)
    }

    func tableView(_ tableView: UITableView, canPerformAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) -> Bool {
        return true
    }

    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        self.clearAllSelectedCell()
    }

但是我的要求是做到这一点：

我该如何实现？

Answer 1

您的代码有些错误……

不使用UIMenuController.shared.menuItems?.append，只需设置menuItems
不要在shouldShowMenuForRowAt中执行此操作，只需在viewDidLoad中执行一次
您不需要setMenuVisible

最重要的是

菜单项的操作必须是表视图单元格子类上的方法。

所以，就您而言...

您的表视图控制器应具有以下方法...

override func viewDidLoad() {
    super.viewDidLoad()

    let forward = UIMenuItem(title: "Forward", action: #selector(MyCell.menuItemTapped(_ :)))
    let delete = UIMenuItem(title: "Delete", action: #selector(MyCell.menuItemTapped(_ :)))
    UIMenuController.shared.menuItems = [forward, delete]
    UIMenuController.shared.update()
}

override func tableView(_ tableView: UITableView, shouldShowMenuForRowAt indexPath: IndexPath) -> Bool {
    return true
}

override func tableView(_ tableView: UITableView, performAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) {
}

override func tableView(_ tableView: UITableView, canPerformAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) -> Bool {
    return true
}

您的手机应该有……

class MyCell: UITableViewCell {
    @objc func menuItemTapped(_ sender: UIMenuController) {
    }
}

Answer 2

1.  create protocol to provide control into your view controller :

public protocol MenuItemDelegate {
    func copyAction(cell: UITableViewCell)
    func forwordAction(cell: UITableViewCell)
    func deleteAction(cell: UITableViewCell)
}

2.  create a custom table cell:

        class MyTableCell: UITableViewCell {

            var menuItemDelegate: MenuItemDelegate!

            var isCopyEnable = true
            var isForwardEnable = true
            var isDeleteEnable = true


            override func awakeFromNib() {
                super.awakeFromNib()
            }

            func setUpmenu(){
                let menu = UIMenuController.shared
                let forword = UIMenuItem(title: "Forward", action: #selector(self.forword(_:)))
                let delete = UIMenuItem(title: "Delete", action: #selector(self.deleteAction(_:)))
                menu.menuItems = [forword,delete]
                if !isDeleteEnable{
                    menu.menuItems?.remove(at: (menu.menuItems?.index(of: delete))!)
                }
                if !isForwardEnable{
                    menu.menuItems?.remove(at: (menu.menuItems?.index(of: forword))!)
                }
                menu.update()
            }

            override public func copy(_ sender: Any?) {
                UIPasteboard.general.string = accessibilityValue
                menuItemDelegate.copyAction(cell: self)
                UIMenuController.shared.setMenuVisible(false, animated: true)
            }

            @objc public func forword(_ sender: Any?) {
                menuItemDelegate.forwordAction(cell: self)
                UIMenuController.shared.setMenuVisible(false, animated: true)
            }

            @objc public func deleteAction(_ sender: Any?) {
                menuItemDelegate.deleteAction(cell: self)
                UIMenuController.shared.setMenuVisible(false, animated: true)
            }

            override public func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
                return (action == #selector(copy(_:))  || action == #selector(forword(_:)) || action == #selector(deleteAction(_:)))
            }
    }

3. Implement in view controller as like : 


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "MyTableCell", for: indexPath) as! MyTableCell
    cell.isForwardEnable = false
    cell.setUpmenu()
    return cell
}

func tableView(_ tableView: UITableView, shouldShowMenuForRowAt indexPath: IndexPath) -> Bool {
    return true
}

func tableView(_ tableView: UITableView, performAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) {
    UIMenuController.shared.setMenuVisible(true, animated: true)
}

func tableView(_ tableView: UITableView, canPerformAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) -> Bool {
    return true
}

它将帮助您实现这一目标。

Answer 3

请按照以下步骤操作，长按即可获得自定义项目。

将以下代码粘贴到viewDidload方法中让reply = UIMenuItem（标题：“ Reply”，操作：#selector（MessageCollectionViewCell.reply（_ :)））让edit = UIMenuItem（title：“ Edit”，action：#selector（MessageCollectionViewCell.edit（_ :)）） let forward = UIMenuItem（title：“ Forward”，action：#selector（MessageCollectionViewCell.forward（_ :)）） UIMenuController.shared.menuItems = [回复，编辑，转发] UIMenuController.shared.update（）
自定义单元格的扩展名扩展MessageCollectionViewCell {

@objc func回复（_发件人：可以吗？）{     //获取collectionView     如果让collectionView = self.superview为？ UICollectionView {         //获取indexPath         如果让indexPath = collectionView.indexPath（for：self）{             //触发动作             collectionView.delegate？.collectionView？（collectionView，performAction：#selector（MessageCollectionViewCell.reply（_ :)），forItemAt：indexPath，withSender：sender）         }     } }

@objc func edit（_ sender：Any？）{     //获取collectionView     如果让collectionView = self.superview为？ UICollectionView {         //获取indexPath         如果让indexPath = collectionView.indexPath（for：self）{             //触发动作             collectionView.delegate？.collectionView？（collectionView，performAction：#selector（MessageCollectionViewCell.edit（_ :)），forItemAt：indexPath，withSender：sender）         }     } }

@objc func forward（_发件人：可以吗？）{     //获取collectionView     如果让collectionView = self.superview为？ UICollectionView {         //获取indexPath         如果让indexPath = collectionView.indexPath（for：self）{             //触发动作             collectionView.delegate？.collectionView？（collectionView，performAction：#selector（MessageCollectionViewCell.forward（_ :)），forItemAt：indexPath，withSender：sender）         }     } }

}

在我的情况下，将此代码添加到您的控制器中（这样做是（类ChatViewController：MessagesViewController {}）

// --------------------------------------------- ------------------------------------------- // MARK：-处理长按动作 // ------------------------------------------------ ---------------------------------------- 覆盖func collectionView（_ collectionView：UICollectionView，shouldShowMenuForItemAt indexPath：IndexPath）-> Bool { 返回真 }

重写func collectionView（_ collectionView：UICollectionView，canPerformAction操作：选择器，forItemAt indexPath：IndexPath，withSender发送者：Any？）-> Bool { 打印（action.description）让message = messages [indexPath.section] //让message = messagesDataSource.messageForItem（位于：indexPath，位于：messagesCollectionView）
```
if action == NSSelectorFromString("reply:") {
    return true
}
else if action == NSSelectorFromString("edit:") {
    return true

}
else if action == NSSelectorFromString("forward:") {
    return true
}
else {
    return super.collectionView(collectionView, canPerformAction: action, forItemAt: indexPath, withSender: sender)
}
```
}

重写func collectionView（_ collectionView：UICollectionView，performAction操作：选择器，forItemAt indexPath：IndexPath，withSender发送者：任何？）{
```
if action == NSSelectorFromString("reply:") {
    print("reply item here!!")
}
else if action == NSSelectorFromString("edit:") {
    print("edit item here!!")
}
else if action == NSSelectorFromString("forward:") {
    print("forward item here!!")
}
else {
    super.collectionView(collectionView, performAction: action, forItemAt: indexPath, withSender: sender)
}
```
}

更新UIMenuController中的菜单项

3 个答案: