Golang:对接口切片进行排序

时间:2018-10-10 13:56:22

标签: sorting go interface slice

我实现了一个界面几何,并有一部分[]几何,

anything := []geometry{
        rect{width: 3, height: 4, name: "rect"},
        circle{radius: 5, name: "circle"},
}

现在我要按名称对切片进行排序,更改切片中元素的顺序。我可以使用getName函数来获取名称。排序后,我希望它像片一样

{circle{radius: 5, name: "circle"},rect{width: 3, height: 4, name: "rect"},}

这是代码

package main

import (
    "fmt"
    "math"
    "sort"
)

type geometry interface {
    area() float64
    perim() float64
    getName() string
}

type rect struct {
    width, height float64
    name          string
}

type circle struct {
    radius float64
    name   string
}

func (r rect) area() float64 {
    return r.width * r.height
}
func (r rect) perim() float64 {
    return 2*r.width + 2*r.height
}
func (r rect) getName() string {
    return r.name
}

func (c circle) area() float64 {
    return math.Pi * c.radius * c.radius
}
func (c circle) perim() float64 {
    return 2 * math.Pi * c.radius
}
func (c circle) getName() string {
    return c.name
}

func main() {
    anything := []geometry{
        rect{width: 3, height: 4, name: "rect"},
        circle{radius: 5, name: "circle"},
    }
    for i := range anything {
        fmt.Println(anything[i].getName())
    }
}

1 个答案:

答案 0 :(得分:3)

对于sort.Slice(...)来说,这是一项简单的任务,与此处的示例非常相似!

您需要做的就是用您的“ anything”切片和一个“ Less”函数调用该函数,该函数比较anything[x].getName()的结果。

例如(Go Playground):

sort.Slice(anything, func(i, j int) bool {
  return anything[i].getName() < anything[j].getName()
})
// Now the items in "anything" are sorted alphabetically by name.