Question

我正在尝试重组一些代码。现在看起来像这样：

async function myfunction(ref) {
  var r1 = await getReport(ref, "queue", "hour", "2018-10-03", "2018-10-04", "pageviews", "page");
  var r2 = await getReport(r1.reportID, "get").then(r2 => reportHandler(r1.reportID, r2, 0));
  return r2;
}

const data= await myFunction(ref);
if(data!=null && data.report.data!=null){
  const result = data.report.data.reduce((r, e) => {
    e.breakdownTotal.forEach(el => {
      let key = "data";
      if(!r[key]) r[key] = []
      r[key].push(...el.counts)
    })
    return r;
  }, {})
}

但是，我想将其重组为单个函数，如下所示：

async function myfunction(ref) {
  var r1 = await getReport(ref, "queue", "hour", "2018-10-03", "2018-10-04", "pageviews", "page");
  var r2 = await getReport(r1.reportID, "get").then(r2 => reportHandler(r1.reportID, r2, 0));
  if(r2!=null && r2.report.data!=null) {
    const result = r2.report.data.reduce((r, e) => {
      e.breakdownTotal.forEach(el => {
        let key = "data";
        if(!r[key]) r[key] = []
        r[key].push(...el.counts)
      })
      return r;
    }, {})
  }
}

但是我没有运气让它工作。在这种情况下，我会收到此错误：

mytest3.html：10未捕获（承诺）TypeError：无法读取属性未定义的“数据” 在myfunction（mytest3.html：10）

报告处理程序代码：

async function reportHandler(id, r2, retries) {
  if (retries >= 3 || r2.error != "report_not_ready") return r2;
  await sleep(2000);
  var report = await getReport(id, "get");
  return reportHandler(id, report, retries + 1);
}

重构代码以在功能内部移动代码会导致未定义的错误

0 个答案: