Question

我对awk相当陌生，我的意图是对文件中的以下内容执行模式匹配。该模式应获取任何具有 vdd *或vss * 的行我尝试在awk中跟踪模式 vdd ，但是没有用。

if(($1~"inout/svdd") || ($1~"input/svdd") || ($1~"output/svdd")) {
do_something
}

样本输入：

  input tprImeasbuf;
  output ibias7;
  inout vssd;
  output vddpminvref;
  input disablevdda1v8;
  output ibiaspowerreferencescp5;
  output vddaok;
  input tprImeasPLL;
  inout mtp_isense;
  output ibiaspowerreferencescp3;
  output enablelevelshifts;
  output poff;
  inout vddp;
  input ResGainSel412;
  output icasc_ch5;
  inout Rref;
  output icasc_ch3;
  output ibiasshutdowncomparator;
  output vdddok;
  input tpr_vbgbufout;
  output iref3v3_ch4;
  inout atb5;
  input tprIrefcurbuf;
  output ibiaspowerreference4;
  input tpr_vdddcompextref;
  input tprIrefcurPLL;

预期输出：

vssd
vddpminvref
vddaok
vddp
vdddok

Answer 1

const layers = ["layer1", "layer2", "layer3"];

async function connect(layer: string): Promise<object> {
    return new Promise((resolve, reject) => {
        setTimeout(function () {
            resolve(layer);
        }, 1000);
    });
}

(async function () {
    for (let i = 0; i < layers.length; i++) {
        const result = await connect(layers[i]);
        console.log(result, "connected");
    }
    console.log("All layers are connected");
})();

console.log('Loading function'); const AWS = require('aws-sdk'); const awsConfig = { region: 'us-west-2', apiVersion: '2012-08-10', }; AWS.config.update(awsConfig); const s3 = new AWS.S3(); const bucket = 'uis-prime-test'; // const uniqueId = Math.floor(Math.random() * 100000); // initially create the map without any key const map = {}; function addValueToList(key, value) { // if the list is already created for the "key", then uses it // else creates new list for the "key" to store multiple values in it. map[key] = map[key] || []; map[key].push(value); } function getS3Key(payload) { const json = JSON.parse(payload); const creationDateTime = new Date(json.executionContext.creationDateTime); const year = creationDateTime.getUTCFullYear(); let month = creationDateTime.getUTCMonth() + 1; const day = creationDateTime.getUTCDate(); const hour = creationDateTime.getUTCHours(); if (month < 10) { month = `0${month}`; } return `${year}/${month}/${day}/${hour}/`; } exports.handler = function (event, context) { try { const uniqueId = context.awsRequestId; event.Records.forEach((record) => { const payload = Buffer.from(record.kinesis.data, 'base64').toString('ascii'); const key = getS3Key(payload) + uniqueId; addValueToList(key, payload.toString()); }); Object.entries(map).forEach(([key, value]) => { const params = { Bucket: bucket, Key: key, Body: value.join('\n') }; s3.putObject(params, (err, data) => { if (err) { throw err; } else { console.log('Successfully uploaded data'); } }); }); } catch (err) { console.log(err); } return `Successfully processed ${event.Records.length} records.`; };用于处理您发布的样本输入使用$ awk '$2~/^v(ss|dd)/{sub(/;\r$/,"",$2); print $2}' file vssd vddpminvref vddaok vddp vdddok换行符的事实。如果实际输入中不是这种情况，则只需删除\r。我强烈建议您在文件上运行\r\n来剥离这些\r，然后再在其上运行awk或任何其他UNIX工具。

Answer 2

这是您所期望的吗？

$ awk -F" " ' $0~/vdd|vss/ { print } ' in_file
  inout vssd;
  output vddpminvref;
  input disablevdda1v8;
  output vddaok;
  inout vddp;
  output vdddok;
  input tpr_vdddcompextref;

$

EDIT1：

$ awk -F" " ' $1~/input|inout|output/ && $2~/^(vdd|vss)/ { print } ' in_file
  inout vssd;
  output vddpminvref;
  output vddaok;
  inout vddp;
  output vdddok;

Answer 3

您可能想使用grep进行这种简单的模式匹配：

grep -o -E ' v(dd|ss)[^ ;]*' file

-o用于打印匹配的正则表达式（而不是整行）。

-E启用扩展正则表达式（ERE）。

awk：如何使用空格进行模式匹配

3 个答案: