Question

我想创建数据，但是如果数据已经存在于数据库中，它将进行更新。但是，如果数据尚未存储在数据库中，它将创建新数据。

这是我的控制器

public function store(Request $request)
{      
    $real = SpentTime::findOrCreate([
        'plan_id' => $request->get ('plan_id'),
        'daily_spent_time' => $request->get ('daily_spent_time'),
        'daily_percentage' => $request->get ('daily_percentage'),
        'reason' => $request->get ('reason')
    ]);

    return redirect()->route('real.index', compact( 'reals'));
}

这是我的模特

public static function findOrCreate($plan_id)
{
    $real = SpentTime::find($plan_id);
    return $real ?: new SpentTime;
}

当我已经在数据库中创建数据时，数据不会更新。

Answer 1

尝试这样

$user = User::firstOrNew(array('name' => Input::get('name')));
$user->foo = Input::get('foo');
$user->save()

Answer 2

尝试这个

public function store(Request $request)
{      
    $real = SpentTime::findOrCreate($request->get('plan_id'),[
        'plan_id' => $request->get ('plan_id'),
        'daily_spent_time' => $request->get ('daily_spent_time'),
        'daily_percentage' => $request->get ('daily_percentage'),
        'reason' => $request->get ('reason')
    ]);

    return redirect()->route('real.index', compact( 'reals'));
}

public static function findOrCreate($plan_id,$data)
{
    $real = static::where('plan_id',$plan_id)->first();
    if (is_null($real)) {
        return static::create($data);
    } else {
        return $real->update($data);
    }
}

在laravel中查找或创建

2 个答案: