如何从已经创建实例的类中调用静态异步函数？

Question

处理程序类具有试图通过传递必需的参数来调用的过程，但看来我做不到，在以下情况下，什么方法正确？

为什么我不能在main中执行GetAccountBalanceHandler .process？

handler.ts

    export class GetAccountBalanceHandler extends Controller {
        public static async process(@Request() request: any,
                                    response: any): Promise<any> {
            try {
                const instance = new GetAccountBalanceHandler();
                const data = await instance.execute(request);
                response.status(200);
                response.send(data);
            } catch (err) {
                response.status(200);
                response.send(err.message);
            }

        }

        constructor() {
            super();
        }

// execute stuff
    }

main.ts

import {handler} "./handler"
  export class GetAccountBalanceController extends Controller {
    public static async process(@Request() request: ExpressRequest,
                                response: ExpressResponse): Promise<any> {
        try {
            const instance = new GetAccountBalanceController();
            const data = await this.BalanceResponse(request);
            response.status(200);
            response.send(data);
        } catch (err) {
            response.status(200);
            response.send(err.message);
        }

    }

    constructor() {
        super();
    }
   private async BalanceResponse(_request: any): Promise<any> {
        return await GetAccountBalanceHandler .process(_request);
    }

}