Question

我有一个文本文件。它包含这样的一行：-

I don't want to see this line 1 and next line.
exception: 14
I want to see this line 1 and next line.
exception: 16
I don't want to see this line 2 and next line.
exception: 13
I want to see this line 2 and next line.
exception: 19

我想要这样的输出：-

I want to see this line 1 and next line.
exception: 16
I want to see this line 2 and next line.
exception 19

我试图用awk解决它。但是不能得到正确的结果。我的awk脚本：

$ cat test.awk  
awk '
  {if ( $2 > 14 )  print prev $0; next}
' test.txt

结果：

$ ./test.awk
I don't want to see this line 1 and next line.
I want to see this line 1 and next line.
exception: 16
I don't want to see this line 2 and next line.
I want to see this line 2 and next line.
exception: 19

Answer 1

如果您想为此使用awk，那么您会遗漏一些小东西，而不必定义prev：

awk '/^exception:/ && ($NF > 14) {print prev; print $0} {prev = $0}' file

您还应该说您的行应以exception:开头，否则，当您有这样的行时可能会遇到问题

exception: 2
Some 15 years ago I had an exception
exception: 1

这将打印出错误的内容。

否则，请使用grep（请参阅How do you grep a file and get the next 5 lines）

如果下一行匹配特殊条件，如何输出当前行和下一行

1 个答案: