Question

这是我的javascript函数，我在其中传递参数，使用警报，我检查该函数正在获取所需的参数，但无法以django url传递它们，否则将字符串传递给url，但不能与参数一起使用。

      function myFunction(a) {
      var v = a.value;
      alert(v);
      location.href="{% url 'new_event' v %}"; //does not works
      location.href="{% url 'new_event' 'string' %}"; //works
      }

我已经检查了获取值的方式是我想要的字符串，但是如何传递呢？

Answer 1

请尝试一下：

    function myFunction(a) {
        var v = a.value;
        alert(v);
        location.href="{% url 'new_event' v %}"; // this will not work because your django **url** filter is pre-processed on your server while your javascript variable is processed on **client**
        // if you want your variable v to be dynamic, you need to include it in your django's view **context**
        location.href="{% url 'new_event' 'string' %}"; //works
    }

    // include in your views.py
    context['v'] = 'some-string'

    // template.html
    <script>
        function myFunction(a) {
            var v = '{{ v }}'; // javascript variable v
            alert(v);
            location.href="{% url 'new_event' v %}"; // django context variable v
        }
    </script>

Answer 2

使用确切的网址，即new / value1 / value2 /

Answer 3

使用

location.href = "/" + v

其中 v 是您的 id 或 slug

通过带有参数的javascript调用Django URL

3 个答案: