如何通过选择菜单上的项目调用视图？

Question

以下是显示“选择菜单”的视图，该菜单将根据所选过滤器调用另一个视图：

    <form action="<?= base_url() ?>process/processfilter" method="post" >
                <div class="col-md-2" >
                    <div class="form-group">
                        <label>Filter</label>
                        <select class="form-control" name="situation" required autofocus>                    
                            <option value="All">List All</option> Here I'd like to call another method that has no filter.
                            <option value="Processing">Processing</option>                                                    
                            <option value="Concluded">Concluded</option>
                            <option value="Archived">Archived</option>  
                        </select>
                    </div>
                </div>
            </form>

控制器类中的功能：

public function processfilter($situation) {
$this->load->model('ProcessModel', 'processo');
        $dados['process'] = $this->process->getProcess($situation);
if ($this->process->getProcess($situation)) {
$this->load->view('/reports/process', $dados);
  } else {
            redirect('dashboard', 'refresh');
        }
    }

类模型中的功能

function getProcesss($situation) {
    $this->db->select('*');
    $this->db->where("situation", $situation); 
    return $this->db->get('process')->result();
}

  

注意：我需要像在Excel中那样在视图中进行过滤。