Question

我在NodeMCU上有一个简单的工作代码：

    void setup() {
  Serial.begin(9600);
  // initialize digital pin 13 as an output.
  pinMode(13, OUTPUT);
}

// the loop function runs over and over again forever
void loop() {

//  Serial.println("Let's turn on the LED Light");
//  delay(1000);              // wait for a second
//  digitalWrite(13, HIGH);   // turn the LED on (HIGH is the voltage level)
//  delay(5000);              // wait for a second
//  Serial.println("Let's turn off the LED Light");
//  delay(1000);              // wait for a second
//  digitalWrite(13, LOW);    // turn the LED off by making the voltage LOW
//  delay(5000);              // wait for a second


  int sensorValue = analogRead(A0);   // read the input on analog pin 0

  float voltage = sensorValue * (5.0 / 1023.0);   // Convert the analog reading (which goes from 0 - 1023) to a voltage (0 - 5V)

  float lux = voltage * 100;

//  Serial.println(voltage);   // print out the value you read
//  Serial.println(lux);
//  delay(1000);

  if (lux > 150)
   {
//    Serial.println(lux);

   digitalWrite(13, HIGH);   // turn the LED on (HIGH is the voltage level)
   }

  else
{
    digitalWrite(13, LOW);    // turn the LED off by making the voltage LOW
   }


}

这确实非常好，每当LDR看到的光大于150时，它就会打开LED，但是.....

如何使millis（）计算LED点亮的时间/该值大于150？

我想在1分钟：52秒：152英里中显示时间，但是直到该值再次低于150（LED熄灭）时才显示时间。

有人可以帮助我吗？

nodeMCU-Millis（）-简单计数器-LED点亮多长时间

0 个答案: