我有一个地图矢量(xml / parse的结果),其中包含以下嵌套地图矢量(我已经摆脱了一些我不想保留的部分):
[
{:tag :SoapObject, :attrs nil, :content [
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["ID"]}
{:tag :FieldValue, :attrs nil, :content ["8d8edbb6-cb0f-11e8-a8d5-f2801f1b9fd1"]}
]}
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["Attribute_1"]}
{:tag :FieldValue, :attrs nil, :content ["Value_1a"]}
]}
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["Attribute_2"]}
{:tag :FieldValue, :attrs nil, :content ["Value_2a"]}
]}
]}
{:tag :SoapObject, :attrs nil, :content [
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["ID"]}
{:tag :FieldValue, :attrs nil, :content ["90e39036-cb0f-11e8-a8d5-f2801f1b9fd1"]}
]}
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["Attribute_1"]}
{:tag :FieldValue, :attrs nil, :content ["Value_1b"]}
]}
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["Attribute_2"]}
{:tag :FieldValue, :attrs nil, :content ["Value_2b"]}
]}
]}
]
现在,我只想从此结构中提取一些特定数据,以产生如下所示的结果:
[
{"ID" "8d8edbb6-cb0f-11e8-a8d5-f2801f1b9fd1",
"Attribute_1" "Value_1a",
"Attribute_2" "Value_1a"}
{"ID" "90e39036-cb0f-11e8-a8d5-f2801f1b9fd1",
"Attribute_1" "Value_1b",
"Attribute_2" "Value_1b"}
]
哪种clojure工具可以帮助我完成此任务?
我发现another question有点类似,但是每当我尝试某个版本的map调用时,我得到的结果都是某种clojure.lang.LazySeq或clojure.core $ map,我无法无法正确打印以验证结果。
答案 0 :(得分:3)
通常您可以从底部开始,然后逐渐上升:
首先,您想解析attr项:
(def first-content (comp first :content))
(defn get-attr [{[k v] :content}]
[(first-content k)
(first-content v)])
user> (get-attr {:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["ID"]}
{:tag :FieldValue, :attrs nil, :content ["90e39036-cb0f-11e8-a8d5-f2801f1b9fd1"]}
]})
;;=> ["ID" "90e39036-cb0f-11e8-a8d5-f2801f1b9fd1"]
然后,您将把每一项变成一张attrs地图:
(defn parse-item [item]
(into {} (map get-attr (:content item))))
(parse-item {:tag :SoapObject, :attrs nil, :content [
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["ID"]}
{:tag :FieldValue, :attrs nil, :content ["90e39036-cb0f-11e8-a8d5-f2801f1b9fd1"]}
]}
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["Attribute_1"]}
{:tag :FieldValue, :attrs nil, :content ["Value_1b"]}
]}
{:tag :ObjectData, :attrs nil, :content [
{:tag :FieldName, :attrs nil, :content ["Attribute_2"]}
{:tag :FieldValue, :attrs nil, :content ["Value_2b"]}
]}
]})
;;=> {"ID" "90e39036-cb0f-11e8-a8d5-f2801f1b9fd1", "Attribute_1" "Value_1b", "Attribute_2" "Value_2b"}
因此,您需要做的最后一件事是映射到顶层表单,生成所需的结果:
(mapv parse-item data)
;;=> [{"ID" "8d8edbb6-cb0f-11e8-a8d5-f2801f1b9fd1", "Attribute_1" "Value_1a", "Attribute_2" "Value_2a"}
;; {"ID" "90e39036-cb0f-11e8-a8d5-f2801f1b9fd1", "Attribute_1" "Value_1b", "Attribute_2" "Value_2b"}]
答案 1 :(得分:0)
您可以使用Tupelo Forest库轻松解决基于树的问题。您可以看到视频介绍from last year's Clojure Conj here。
对于您的问题,我将按以下方式处理。首先,数据:
(dotest
(let [data-enlive
{:tag :root
:attrs nil
:content
[{:tag :SoapObject, :attrs nil,
:content
[{:tag :ObjectData, :attrs nil,
:content [{:tag :FieldName, :attrs nil, :content ["ID"]}
{:tag :FieldValue, :attrs nil, :content ["8d8edbb6-cb0f-11e8-a8d5-f2801f1b9fd1"]}]}
{:tag :ObjectData, :attrs nil,
:content [{:tag :FieldName, :attrs nil, :content ["Attribute_1"]}
{:tag :FieldValue, :attrs nil, :content ["Value_1a"]}]}
{:tag :ObjectData, :attrs nil,
:content [{:tag :FieldName, :attrs nil, :content ["Attribute_2"]}
{:tag :FieldValue, :attrs nil, :content ["Value_2a"]}]}]}
{:tag :SoapObject, :attrs nil,
:content
[{:tag :ObjectData, :attrs nil,
:content [{:tag :FieldName, :attrs nil, :content ["ID"]}
{:tag :FieldValue, :attrs nil, :content ["90e39036-cb0f-11e8-a8d5-f2801f1b9fd1"]}]}
{:tag :ObjectData, :attrs nil,
:content [{:tag :FieldName, :attrs nil, :content ["Attribute_1"]}
{:tag :FieldValue, :attrs nil, :content ["Value_1b"]}]}
{:tag :ObjectData, :attrs nil,
:content [{:tag :FieldName, :attrs nil, :content ["Attribute_2"]}
{:tag :FieldValue, :attrs nil, :content ["Value_2b"]}]}]}]}]
然后是代码
(with-debug-hid
(with-forest (new-forest)
(let [root-hid (add-tree-enlive data-enlive)
soapobj-hids (find-hids root-hid [:root :SoapObject])
objdata->map (fn [objdata-hid]
(let [fieldname-node (hid->node (find-hid objdata-hid [:ObjectData :FieldName]))
fieldvalue-node (hid->node (find-hid objdata-hid [:ObjectData :FieldValue]))]
{ (grab :value fieldname-node) (grab :value fieldvalue-node) }))
soapobj->map (fn [soapobj-hid]
(apply glue
(for [objdata-hid (hid->kids soapobj-hid)]
(objdata->map objdata-hid))))
results (mapv soapobj->map soapobj-hids)]
有中间结果:
(is= (hid->bush root-hid)
[{:tag :root}
[{:tag :SoapObject}
[{:tag :ObjectData}
[{:tag :FieldName, :value "ID"}]
[{:tag :FieldValue, :value "8d8edbb6-cb0f-11e8-a8d5-f2801f1b9fd1"}]]
[{:tag :ObjectData}
[{:tag :FieldName, :value "Attribute_1"}]
[{:tag :FieldValue, :value "Value_1a"}]]
[{:tag :ObjectData}
[{:tag :FieldName, :value "Attribute_2"}]
[{:tag :FieldValue, :value "Value_2a"}]]]
[{:tag :SoapObject}
[{:tag :ObjectData}
[{:tag :FieldName, :value "ID"}]
[{:tag :FieldValue, :value "90e39036-cb0f-11e8-a8d5-f2801f1b9fd1"}]]
[{:tag :ObjectData}
[{:tag :FieldName, :value "Attribute_1"}]
[{:tag :FieldValue, :value "Value_1b"}]]
[{:tag :ObjectData}
[{:tag :FieldName, :value "Attribute_2"}]
[{:tag :FieldValue, :value "Value_2b"}]]]])
(is= soapobj-hids [:0009 :0013])
和最终结果:
(is= results
[{"ID" "8d8edbb6-cb0f-11e8-a8d5-f2801f1b9fd1",
"Attribute_1" "Value_1a",
"Attribute_2" "Value_2a"}
{"ID" "90e39036-cb0f-11e8-a8d5-f2801f1b9fd1",
"Attribute_1" "Value_1b",
"Attribute_2" "Value_2b"}]))))))
更多文档仍在进行中,但是您可以see API docs here和live example of your problem here。
答案 2 :(得分:0)
您也可以组成换能器。前几天,我在JUXT博客上阅读了一些有关使用换能器创建xpath之类功能的信息。
webpack: {
module: {
rules: [
{ test: /\.js/, exclude: /node_modules/, loader: 'babel-loader' }
]
},
watch: true,
mode: 'none'
},
答案 3 :(得分:0)
这里不需要精美的工具。您可以摆脱最简单的代码块。
(use '[plumbing.core])
(let [A ...your-data...]
(map (fn->> :content
(mapcat :content)
(mapcat :content)
(apply hash-map))
A))
答案 4 :(得分:0)
使用perc
,您可以执行以下操作:
(->> original-data
(mapv
#%/%(->> %:content
(map
#%/$(->> $:content
(apply
#%/?{(first ?1:content)
(first ?2:content)})))
(apply merge))))
它看起来似乎有些惯用,但方式有所不同。