Question

我正在使用此模式创建单例以帮助我进行Firebase操作，但不幸的是，它正在泄漏内存，这是我的代码。

class FirebaseDataSource(private val db: FirebaseFirestore,
                     private val firebaseAuth: FirebaseAuth,
                     private val firebaseFunctions: FirebaseFunctions,
                     private val firebaseStorage: FirebaseStorage,
                     private val firebaseInstanceId: FirebaseInstanceId) {
companion object {

    @Volatile
    private var INSTANCE: FirebaseDataSource? = null


    fun getInstance(db: FirebaseFirestore = FirebaseFirestore.getInstance(),
                    firebaseAuth: FirebaseAuth = FirebaseAuth.getInstance(),
                    firebaseFunctions: FirebaseFunctions = FirebaseFunctions.getInstance(),
                    firebaseStorage: FirebaseStorage = FirebaseStorage.getInstance(),
                    firebaseInstanceId: FirebaseInstanceId = FirebaseInstanceId.getInstance()
    ): FirebaseDataSource =
            INSTANCE ?: synchronized(this) {
                INSTANCE
                        ?: FirebaseDataSource(db, firebaseAuth, firebaseFunctions, firebaseStorage, firebaseInstanceId).also { INSTANCE = it }
            }

    fun clearInstance() {
        INSTANCE = null
    }
}
}

并且我在这样的活动中使用它

private val firebaseDataSource = FirebaseDataSource.getInstance()

可以帮助我解决内存泄漏甚至为FirebaseDataSource设计更好的方法

Answer 1

Kotlin具有顶层，线程安全的单例对象。为什么不尝试这样的事情：

object FirebaseDataSource {
  private val db: FirebaseFirestore = FirebaseFirestore.getInstance()
  private val firebaseAuth: FirebaseAuth = FirebaseAuth.getInstance()
  private val firebaseFunctions: FirebaseFunctions = FirebaseFunctions.getInstance()
  private val firebaseStorage: FirebaseStorage = FirebaseStorage.getInstance()
  private val firebaseInstanceId: FirebaseInstanceId = FirebaseInstanceId.getInstance()

  fun doStuff() {
    db.doStuff()
  }
}

然后使用它

FirebaseDataSource.doStuff()

Leak Canary检测到Kotlin Singleton泄漏内存

1 个答案: