Question

我想获取end time的{{1}}与下一个id之间的时间间隔。

start time

import pandas as pd df = pd.DataFrame({'id':[1,1,2,2,2],'startTime': ['2017-03-09 10:05:23', '2017-03-09 10:09:53', '2017-03-09 10:11:03' , '2017-03-09 10:41:04' , '2017-03-09 17:02:56' ], 'endTime':['2017-03-09 10:05:33' , '2017-03-09 10:09:58' , '2017-03-09 10:29:43' , '2017-03-09 12:41:24' , '2017-03-09 17:03:21' ]}) print(df)

Input:

id startTime endTime 0 1 2017-03-09 10:05:23 2017-03-09 10:05:33 1 1 2017-03-09 10:09:53 2017-03-09 10:09:58 2 2 2017-03-09 10:11:03 2017-03-09 10:29:43 3 2 2017-03-09 10:41:04 2017-03-09 12:41:24 4 2 2017-03-09 17:02:56 2017-03-09 17:03:21

Expected:

Answer 1

使用：

#create index by column id
df = df.set_index('id')
#convert columns to datetimes and shift startTime per groups 
df['startTime'] = pd.to_datetime(df['startTime']).groupby(level=0).shift(-1)
df['endTime'] = pd.to_datetime(df['endTime'])

#subtract, remove first missing values per groups and set column from index
df = df['startTime'].sub(df['endTime']).dropna().reset_index(name='time')
print (df)
   id     time
0   1 00:04:20
1   2 00:11:21
2   2 04:21:32

如何按组计算熊猫的开始时间和结束时间之间的时差？

1 个答案: