我想使用RSS提要在其他网站上使用jQuery显示图像
XML RSS结构类似于
<rss version="2.0">
<channel>
<title>Gallery</title>
<link>http://www.example.com</link>
<description> Latest Photos</description>
<item>
<title>First Title of Photo</title>
<link >https://www.example.com/image/gallery/1.jpg </link>
<pubDate>Sun, 17 Dec 2017 00:00:00 GMT</pubDate>
<description>Description of the image </description>
</item>
<item>
<title>Second Title of Photo</title>
<link >https://www.example.com/image/gallery/2.jpg </link>
<pubDate>Sun, 18 Dec 2017 00:00:00 GMT</pubDate>
<description>Description of the image </description>
</item>
<item>
<title>Third Title of Photo</title>
<link >https://www.example.com/image/gallery/3.jpg </link>
<pubDate>Sun, 18 Dec 2017 00:00:00 GMT</pubDate>
<description>Description of the image </description>
</item>
</channel>
</rss>
我的HTML页面具有以下HTML结构
<div id="feed">
<div class="item">
<img src="image-path"/>
<span class="image-title"></span>
</div>
</div>
如何更改下面的代码以使用上述结构。
$(document).ready(function() {
var url = 'http://www.recruiter.com/feed/career.xml'; //Data in XML format
$.ajax({
type: 'GET',
url: "https://api.rss2json.com/v1/api.json?rss_url=" + url, //For converting default format to JSON format
dataType: 'jsonp', //for making cross domain call
success: function(data) {
alert('Success');
$("#feed").append(data.feed);
console.log(data.feed.description);
}
});
});
答案 0 :(得分:1)
您需要遍历data.items
并将目标数据添加到html中。如底部
$.each(data.items, function(i, item){
$("#feed").append('<div class="item"><img src="'+item.thumbnail+'"/><span class="image-title">'+item.thumbnail+'</span></div>');
});
因此您的代码应更改为:
var url = 'http://www.recruiter.com/feed/career.xml';
$.ajax({
type: 'GET',
url: "https://api.rss2json.com/v1/api.json?rss_url=" + url,
dataType: 'jsonp',
success: function(data) {
$.each(data.items, function(i, item){
$("#feed").append('<div class="item"><img src="'+item.thumbnail+'"/><span class="image-title">'+item.thumbnail+'</span></div>');
});
}
});
在demo中查看结果