Question

我有一个如下数组：

Array
(
[0] => Array
    (
        [record_id] => 3
        [task_date] => 2018-10-02
    )

[1] => Array
    (
        [record_id] => 5
        [task_date] => 2018-10-02
    )

[2] => Array
    (
        [record_id] => 1
        [task_date] => 2018-09-27
    )

)

我希望它采用以下格式：

Array
    (
        [0] => Array
            (
            [0] => Array
            (
                [record_id] => 3
                [task_date] => 2018-10-02
            )
            [1] => Array
            (
                [record_id] => 5
                [task_date] => 2018-10-02
            )
            )
        [1] => Array
         (
               [0] => Array
            (
                [record_id] => 1
                [task_date] => 2018-09-27
            )
         )
    )

以便每个子数组包含相同日期的元素。

Answer 1

这将从数据中收集唯一的日期，然后构建一个数组，将同一日期的软管项目分组：

$data = [
        [
        'record_id' => 3,
        'task_date' => '2018-10-02'
    ],
    [
        'record_id' => 5,
        'task_date' => '2018-10-02'
    ],
    [
        'record_id' => 1,
        'task_date' => '2018-09-27'
    ]
];

$dates = [];
foreach ($data as $item) {
    $dates[] = $item['task_date'];
}

$dates = array_unique($dates);

$out = [];
foreach ($dates as $date) {
    $date_group = [];
    foreach ($data as $item) {
        if ($item['task_date'] == $date) {
            $date_group[] = $item;
        }
    }
    $out[] = $date_group;
}

var_dump($out);

Answer 2

您可以这样做。

$inputArray = array("0"=>array('record_id'=>'3','task_date'=>'28-10-02'),'1'=>array('record_id'=>'3','task_date'=>'28-10-02'),'2'=>array('record_id'=>'3','task_date'=>'28-10-03'));

$outputArray    =   array();
foreach($inputArray as $key=>$value){
    $outputArray[$value['task_date']][]=$value;
}

print_r(array_values($outputArray));

Answer 3

根据@Barry的回答，解决方案可能如下所示：

https://3v4l.org/LLaIS

<?php

$data = [
        [
        'record_id' => 3,
        'task_date' => '2018-10-02'
    ],
    [
        'record_id' => 5,
        'task_date' => '2018-10-02'
    ],
    [
        'record_id' => 1,
        'task_date' => '2018-09-27'
    ]
];

$out = [];
$datesIterated = [];

foreach ($data as $date) {

    if(in_array($date['task_date'], $datesIterated)) {
        continue;
    }


    $out[] = array_values(array_filter($data, function($item) use ($date) {
        if ($item['task_date'] == $date['task_date']) {
            return $item;
        }
    }));

    $datesIterated[] = $date['task_date'];

}

var_dump($out);

我们需要在array_filter的结果上调用array_values以再次实现顺序索引，有关更多信息，请参见this question。

Answer 4

$common = [];
$output = [];
$i = 0;
foreach($input as $key=>$value){
        if(in_array($value['task_date'],$common)){
                $k = array_search($value['task_date'],$common);
                $output[$k][$i] = $value;
        }else{
                $output[][] = $value;
        }
        $common[] = $value['task_date'];
        $i++;
}
print_r($output);

我希望它对您有用。

Answer 5

PHP中的所有数组都是关联的。
打高尔夫球吗？

。

$data = [
  0 => [
    "record_id" => 3,
    "task_date" => "2018-10-02"
  ], 
  1 => [
    "record_id" => 5, 
    "task_date" => "2018-10-02"
  ], 
  2 => [
    "record_id" => 1, 
    "task_date" => "2018-09-27", 
  ]
];

$out = [];

foreach($data as $task)
{
  $out[$task["task_date"]][] = $task;
}

return array_values($out);

在PHP中将关联数组更改为多维数组

5 个答案: