SELECT pv.PropertyID, COUNT(pv.VisitID) AS InitialVisit
FROM tblPAppointments pa INNER JOIN tblPropertyVisit pv ON pv.AppID = pa.AppID
WHERE pv.Status = 0
GROUP BY pv.PropertyID
UNION ALL
SELECT jv.PropertyID, COUNT(jv.JobVistID) AS JobVisit
FROM tblPAppointments pa INNER JOIN tblJobVisits jv ON jv.AppID = pa.AppID
WHERE jv.VisitStatus = 1
GROUP BY jv.PropertyID
我需要在两个单独的列中获取InitialVisit count和JobVisit count.above query只返回两列(PropertyID,InitialVisit)。
答案 0 :(得分:4)
使用NULL作为不占任何输出的列的占位符:
SELECT pv.PropertyID,
COUNT(pv.VisitID) AS InitialVisit,
NULL AS jobvisit
FROM tblPAppointments pa
JOIN tblPropertyVisit pv ON pv.AppID = pa.AppID
WHERE pv.Status = 0
GROUP BY pv.PropertyID
UNION ALL
SELECT jv.PropertyID,
NULL AS initialvisit,
COUNT(jv.JobVistID) AS JobVisit
FROM tblPAppointments pa
JOIN tblJobVisits jv ON jv.AppID = pa.AppID
WHERE jv.VisitStatus = 1
GROUP BY jv.PropertyID
这将返回三列。列别名在第一个查询中是必需的,但在第二个查询中不是 - 我将两者都别名以明确发生了什么。
请注意,在SQL Server中使用NULL这样的NULL将要求您对NULL以外的数据类型使用CAST/CONVERT,因为SQL Server将NULL默认为INT数据类型(奇怪的是)
不使用UNION的备用查询:
SELECT x.propertyid,
COUNT(y.visitid) AS initialvisit,
COUNT(z.jobvisitid) AS jobvisit
FROM (SELECT pv.propertyid
FROM TBLPROPERTYVISIT pv
WHERE EXISTS (SELECT NULL
FROM TBLAPPOINTMENTS a
WHERE a.appid = pv.appid)
UNION
SELECT jv.propertyid
FROM TBLJOBVISIT jv
WHERE EXISTS (SELECT NULL
FROM TBLAPPOINTMENTS a
WHERE a.appid = jv.appid)) x
LEFT JOIN TBLPROPERTYVISIT y ON y.propertyid = x.propertyid
LEFT JOIN TBLJOBVISIT z ON z.propertyid = x.propertyid
GROUP BY x.propertyid
答案 1 :(得分:3)
根本不需要UNION。而且你不使用tblPAppointments
编辑以允许其中一个表中没有行。仍然有一行输出
SELECT
ISNULL(pv2.PropertyID, jv2.PropertyID),
ISNULL(pv2.InitialVisit, 0),
ISNULL(jv2.JobVisit, 0)
FROM
(
SELECT pv.PropertyID, COUNT(pv.VisitID) AS InitialVisit
FROM tblPropertyVisit pv
WHERE pv.Status = 0
GROUP BY pv.PropertyID
) pv2
FULL OUTER JOIN
(
SELECT jv.PropertyID, COUNT(jv.JobVistID) AS JobVisit
FROM tblJobVisits jv
WHERE jv.VisitStatus = 1
GROUP BY jv.PropertyID
) jv2 ON pv2.PropertyID = jv2.PropertyID