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Question

我正在尝试解析这样的JSON对象集合：

{
"stage": [
{
"name": "Stage 1",
"weeks": [
{
 "name": "Week 1",
 "matches": [
  {
   "teams": [
    {
     "name": "San Francisco Shock",
     "score": "0",
     "score_url": "https://overwatchleague.com/matches/10223"
    },
    {
     "name": "Los Angeles Valiant",
     "score": "4",
     "score_url": "https://overwatchleague.com/matches/10223"
    }
   ]
  },
  {
   "teams": [
    {
     "name": "Shanghai Dragons",
     "score": "0",
     "score_url": "https://overwatchleague.com/matches/10224"
    },
    {
     "name": "Los Angeles Gladiators",
     "score": "4",
     "score_url": "https://overwatchleague.com/matches/10224"
    }
   ]
  },
  {
   "teams": [
    {
     "name": "Dallas Fuel",
     "score": "1",
     "score_url": "https://overwatchleague.com/matches/10225"
    },
    {
     "name": "Seoul Dynasty",
     "score": "2",
     "score_url": "https://overwatchleague.com/matches/10225"
    }
   ]
  },

等等，

我正试图将其转换为一种格式，使另一种对JSON不太友好的语言可以通过将其压缩为以下格式来更轻松地处理：

{"matches":
    [
     {
      "team1": "San Francisco Shock",
      "t1score": "0",
      "team2": "Los Angeles Valiant",
      "t2score": "4"
     },
     { ... }
    ]
}

我正在尝试使用此jq过滤器来完成此操作：

jq '.stage[] | {matches: [{team1: .weeks[].matches[].teams[0].name, t1score: 
.weeks[].matches[].teams[0].score, team2: .weeks[].matches[].teams[1].name, 
t2score: .weeks[].matches[].teams[1].score}]}'

与此相关的问题是，它将“名称”键的每个实例与值“ San Francisco Shock”的值匹配到数组“匹配”中所有分数和名称的排列。我对jq还是很陌生，但是我认为这正在发生，因为我只是告诉它通过过滤器将“周”和“匹配”中的所有元素映射在一起。它是否正确？实际执行我想要尝试并看起来像的过滤器是什么？我还没有找到一种简单的方法来使过滤器不匹配超出“团队”数组的范围。

Answer 1

技巧是将.weeks[]迭代器向前“拉”，并在map数组上.matches：

.stage[]
|.weeks[]
| {matches:
    (.matches
     | map({team1:   .teams[0].name,
            t1score: .teams[0].score,
            team2:   .teams[1].name, 
            t2score: .teams[1].score }) ) }

输出

{
  "matches": [
    {
      "team1": "San Francisco Shock",
      "t1score": "0",
      "team2": "Los Angeles Valiant",
      "t2score": "4"
    },
    {
      "team1": "Shanghai Dragons",
      "t1score": "0",
      "team2": "Los Angeles Gladiators",
      "t2score": "4"
    },
    {
      "team1": "Dallas Fuel",
      "t1score": "1",
      "team2": "Seoul Dynasty",
      "t2score": "2"
    }
  ]
}

如何停止JQ筛选器将匹配的键匹配到其他键的每个排列

1 个答案:

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