Employees表包含-
Employee_Id,
Manager_Id,
First_Name,
Last_Name
我想显示经理姓名而不是ID
不能使用LOV
VO中的当前查询:
SELECT
Employees.EMPLOYEE_ID,
Employees.FIRST_NAME,
Employees.LAST_NAME,
JobObject.JOB_TITLE,
Employees.COMMISSION_PCT,
Departments.DEPARTMENT_NAME,
Departments.DEPARTMENT_ID,
JobObject.JOB_ID,
(First_Name||' '||Last_Name) AS VIEW_ATTR,
Employees.SALARY,
Employees.MANAGER_ID
FROM EMPLOYEES Employees,
DEPARTMENTS Departments,
JOBS JobObject
WHERE Employees.DEPARTMENT_ID = Departments.DEPARTMENT_ID
答案 0 :(得分:3)
我假设您要显示“经理姓名”以及员工详细信息。是的,那么下面的查询将很有帮助。
fabric.Image.prototype._renderFill= (function(renderFill){
return function(ctx) {
var w = this.width, h = this.height, sW = w * this._filterScalingX, sH = h * this._filterScalingY,
x = -w / 2, y = -h / 2, elementToDraw = this._element;
y = y + Math.abs((this._element.height-h)/2);
x = x + Math.abs((this._element.width-w)/2);
elementToDraw && ctx.drawImage(elementToDraw,
this.cropX * this._filterScalingX,
this.cropY * this._filterScalingY,
sW,
sH,
x, y, w, h);
}
})()
答案 1 :(得分:0)
如果我理解正确,那么什么都没得到的原因与联接有关,当在FROM子句中使用逗号时,可能会遇到问题。 对于managername,如果您有一个manager表,则必须对其进行内部联接或尝试以下操作:
SELECT Employees.EMPLOYEE_ID,
Employees.FIRST_NAME,
Employees.LAST_NAME,
JobObject.JOB_TITLE,
Employees.COMMISSION_PCT,
Departments.DEPARTMENT_NAME,
Departments.DEPARTMENT_ID,
JobObject.JOB_ID,
(Employees.First_Name+' '+Employees.Last_Name) AS ManagerName,
Employees.SALARY,
Employees.MANAGER_ID
FROM EMPLOYEES Employees,
inner join
DEPARTMENTS Departments on Employees.DEPARTMENT_ID = Departments.DEPARTMENT_ID
left outer join
JOBS JobObject on JobObject.Job_Id=Employees.Job_Id
where Employees.MANAGER_ID is not null and Employees.MANAGER_ID in (EMPLOYEE_ID from employees)