Question

ContactInfo类的数据库中有一个表。现在我想找到其中 customerId = id 和 isDeleted = false

的值

<!-- getInfo.php -->
<?PHP
echo "hello world";
?>

联系信息类别：

 private EntityManager entityManager;
 public ContactInfo findById(long id) {
    CriteriaBuilder builder = entityManager.getCriteriaBuilder();
    CriteriaQuery<ContactInfo> criteria = builder.createQuery( ContactInfo.class );
    Root<ContactInfo> root = criteria.from(ContactInfo.class);
    criteria.select(root).where(
            builder.equal(root.get("customerId"), id),
            builder.equal(root.get("isDeleted"), false)
    );
    return entityManager.createQuery(criteria).getSingleResult();
}

PersonalInfo类：

public class ContactInfo extends BaseInfo {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long cntId;
    @Column(columnDefinition="TEXT",length=4000)
    private String data;
    @OneToOne(fetch = FetchType.LAZY)
    @JoinColumn(name="customer_id")
    private PersonalInfo customer;

    public ContactInfo(){ }
    public ContactInfo(Long id) {
        this.cntId = id;
    }
}

BaseInfo类：

public class PersonalInfo extends BaseInfo {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long customerId;//
    private Long cardId;//
}

如何绕过以下错误。提前致谢。错误

abstract public class BaseInfo {

    @CreatedDate
    private Date createdDate;
    @CreatedBy
    private String createdBy;
    @LastModifiedDate
    private Date modifiedDate;
    @LastModifiedBy
    private String modifiedBy;
    @Column(columnDefinition = "boolean default false", nullable = false)
    private boolean isDeleted;
}

Answer 1

您的 customerId 存在于 PersonalInfo 实体中，因此您的条件查询应如下所示。

criteria.select(root).where(
    builder.equal(root.get("customer").get("customerId"), id)
);

请尝试这个。

我希望这能解决您的问题。

使用CriteriaBuilder提取数据时出现问题

1 个答案: