我正在从Web服务中以以下格式快速读取JSON
[{
"id":1,
"shopName":"test",
"shopBranch":"main",
"shopAddress":"usa",
"shopNumber":"5555555",
"logo":[-1,-40,-1,-32],
"shopPath":"test"
},
{
"id":2,
"shopName":"test",
"shopBranch":"main",
"shopAddress":"usa",
"shopNumber":"66666666",
"logo":[-1,-50,-2,-2],
"shopPath":"test"
}]
我已经设法轻松地读取了所有字符串,但是当涉及徽标部分时,我不确定该怎么办,这是mySQL数据库中的blob字段,表示要在其中检索的图像。快速的用户界面,这是我执行此操作的代码,但我不断遇到错误,无法找到正确的方法:
struct Brand: Decodable {
private enum CodingKeys: String, CodingKey {
case id = "id"
case name = "shopName"
case branch = "shopBranch"
case address = "shopAddress"
case phone = "shopNumber"
case logo = "logo"
case path = "shopPath"
}
let id: Int
let name: String
let branch: String
let address: String
let phone: String
let logo: [String]
let path: String
}
func getBrandsJson() {
let url = URL(string: "http://10.211.55.4:8080/exam/Test")
URLSession.shared.dataTask(with: url!, completionHandler: {(data, response, error) in
guard let data = data, error == nil else {
print(error!);
return
}
print(response.debugDescription)
let decoder = JSONDecoder()
let classes = try! decoder.decode([Brand].self, from: data)
for myClasses in classes {
print(myClasses.branch)
if let imageData:Data = myClasses.logo.data(using:String.Encoding.utf8){
let image = UIImage(data:imageData,scale:1.0)
var imageView : UIImageView!
}
}
}).resume()
}
有人能解释一下如何正确地搜索我但是没有运气的方法
答案 0 :(得分:0)
替换
let logo: [String]
使用
let logo: [Int]
使用错误获取
do {
let classes = try JSONDecoder().decode([Brand].self, from: data)
}
catch {
print(error)
}
答案 1 :(得分:0)
首先,您最好告诉Web服务的服务器端工程师,使用数字数组在JSON中返回二进制数据效率不高,他们应该使用Base-64或类似的东西。
如果他们固执地忽视了您的建议,则最好在自定义解码初始化程序中将其解码为Data
。
struct Brand: Decodable {
private enum CodingKeys: String, CodingKey {
case id = "id"
case name = "shopName"
case branch = "shopBranch"
case address = "shopAddress"
case phone = "shopNumber"
case logo = "logo"
case path = "shopPath"
}
let id: Int
let name: String
let branch: String
let address: String
let phone: String
let logo: Data
let path: String
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
self.id = try container.decode(Int.self, forKey: CodingKeys.id)
self.name = try container.decode(String.self, forKey: CodingKeys.name)
self.branch = try container.decode(String.self, forKey: CodingKeys.branch)
self.address = try container.decode(String.self, forKey: CodingKeys.address)
self.phone = try container.decode(String.self, forKey: CodingKeys.phone)
self.path = try container.decode(String.self, forKey: CodingKeys.path)
//Decode the JSON array of numbers as `[Int8]`
let bytes = try container.decode([Int8].self, forKey: CodingKeys.logo)
//Convert the result into `Data`
self.logo = Data(bytes: bytes.lazy.map{UInt8(bitPattern: $0)})
}
}
您可以将getBrandsJson()
的数据解码部分写为:
let decoder = JSONDecoder()
do {
//You should never use `try!` when working with data returned by server
//Generally, you should not ignore errors or invalid inputs silently
let brands = try decoder.decode([Brand].self, from: data)
for brand in brands {
print(brand)
//Use brand.logo, which is a `Data`
if let image = UIImage(data: brand.logo, scale: 1.0) {
print(image)
//...
} else {
print("invalid binary data as an image")
}
}
} catch {
print(error)
}
我写了几行,用猜测将数字数组解码为Data
。因此,如果您发现我的代码不适用于您实际的data
,请告诉我足够的描述和一些实际数据示例。 (至少,您需要向我展示实际的"logo"
数组中的前几百个元素。)