Question

我正在阅读一个Json，它是像这样的几本字典的列表：

a_list = [ {
    "ID": "20394820938",
    "data": [
      {
        "fruit": "tomato",
        "provider": "walmart",
        "availability": "True",
        "Type": false
      },
      {
        "fruit": " orange ",
        "Type": false
      },
      {
        "fruit": "watermelon",
        "provider": "destination",
        "availability": "cotsco",
        "Type": false
      },
      {
        "fruit": " the watermelon is new",
        "Type": false
      }
    ],
    "API": false,
    "count": 0
  },  
  {
    "ID": "203948lHBFNPO",
    "data": [
      {
        "fruit": "apple",
        "provider": "walmart",
        "availability": "True",
        "Type": false
      },
      {
        "fruit": " this is a tomato ",
        "Type": false
      },
      {
        "fruit": "lemon",
        "provider": "unknown",
        "availability": "cotsco",
        "Type": false
      },
      {
        "fruit": " orange ",
        "Type": false
      },
      {
        "fruit": "banana",
        "provider": "unknown",
        "availability": "unknown",
        "Type": false
      }
    ],
    "API": false,
  }
]

当且仅当词典的子元素之一中包含字符串IM00N时，才如何将apple附加到Json的id值？例如：

a_list = [ {
    "ID": "20394820938",
    "data": [
      {
        "fruit": "tomato",
        "provider": "walmart",
        "availability": "True",
        "Type": false
      },
      {
        "fruit": "apple",
        "Type": false
      },
      {
        "fruit": "watermelon",
        "provider": "destination",
        "availability": "cotsco",
        "Type": false
      },
      {
        "fruit": " the watermelon is new",
        "Type": false
      }
    ],
    "API": false,
    "count": 0
  },  
  {
    "ID": "IM00N-203948lHBFNPO",
    "data": [
      {
        "fruit": "apple",
        "provider": "walmart",
        "availability": "True",
        "Type": false
      },
      {
        "fruit": " this is a tomato ",
        "Type": false
      },
      {
        "fruit": "lemon",
        "provider": "unknown",
        "availability": "cotsco",
        "Type": false
      },
      {
        "fruit": " orange ",
        "Type": false
      },
      {
        "fruit": "banana",
        "provider": "unknown",
        "availability": "unknown",
        "Type": false
      }
    ],
    "API": false,
  }
]

我试图构建一个正则表达式，但是它很困难，因为列表中每个子字典的元素中没有模式。进行这种匹配和替换的正确方法是什么？

Answer 1

您可以使用for循环修改数据：

echo htmlentities('An example <br>'); // This will print - An example &lt; br &gt;
echo htmlentities('µ †');             // This will print -  &micro; &dagger;

如果数据的形状有所不同，以致某些条目没有if let postNote = posts[indexPath.item].postNote { if(postNote.isEmpty) { socialCell.noteTextView.removeFromSuperview() socialCell.postDetailsView.bottomAnchor.constraint(equalTo: socialCell.noteTextView.bottomAnchor).isActive = false socialCell.postDetailsView.bottomAnchor.constraint(equalTo: socialCell.postName.bottomAnchor).isActive = true } }键，则可以捕获for entry in a_list: if any('apple' in item['fruit'] for item in entry['data']): entry['ID'] = 'IM00N-' + entry['ID']或使用fruit

KeyError

给定嵌套Json中的字符串，如何给定特定字符串来更改其ID？

1 个答案: