Android应用程序中的Null对象参考

时间:2018-10-06 03:46:30

标签: java android nosql

Hy Guys

因此,我试图在购物清单应用程序的代码下面获取此代码,但我遇到一个导致应用程序崩溃的错误。

代码:

public void setProduct(Context context, View shoppingListViewFragment, String userEmail, String userName, ListModel shoppingListModel, ItemModel productModel) {
    String listID = shoppingListModel.getListID();
    String listName = shoppingListModel.getListName();
    String itemID = productModel.getItemID();
    String itemName = productModel.getItemName();
    Boolean currentList = productModel.getCurrentList();
    productNameContainer.setText(itemName);

    FirebaseFirestore dbRef = FirebaseFirestore.getInstance();
    DocumentReference itemIdRef = dbRef.collection("products").document(listID)
            .collection("shoppingListProducts").document(itemID);

    itemView.setOnClickListener(view -> {
        Map<String, Object> map = new HashMap<>();
        if (currentList) {
            map.put("currentList", false);
        } else {
            map.put("currentList", true);
        }
        itemIdRef.update(map).addOnSuccessListener(aVoid -> {
            if (currentList) {
                dbRef.collection("shoppingLists").document(userEmail)
                        .collection("userShoppingLists").document(listID).get().addOnCompleteListener(task -> {
                            Map<String, Object> map1 = (Map<String, Object>) task.getResult().get("users");
                            String notificationMessage = userName + " has just bought " + itemName + " from " + listName + "'s list!";
                            UserNotificationsModel userNotificationsModel = new UserNotificationsModel(notificationMessage, userEmail);

                            for (Map.Entry<String, Object> entry : map1.entrySet()) {
                                String sharedUserEmail = entry.getKey();

                                if (!sharedUserEmail.equals(userEmail)) {
                                    dbRef.collection("notifications").document(sharedUserEmail)
                                            .collection("userNotifications").document()
                                            .set(userNotificationsModel);
                                }
                            }
                        });
            }
        });
    });

    itemView.setOnLongClickListener(view -> {
        AlertDialog.Builder builder = new AlertDialog.Builder(context);
        builder.setTitle("Edit / Delete Item");

        EditText editText = new EditText(context);
        editText.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_FLAG_CAP_WORDS);
        editText.setText(itemName);
        editText.setSelection(editText.getText().length());
        editText.setHint("Please type item name");
        editText.setHintTextColor(Color.GRAY);
        builder.setView(editText);

        builder.setPositiveButton("Update", (dialogInterface, i) -> {
            String newItemName = editText.getText().toString().trim();
            Map<String, Object> map = new HashMap<>();
            map.put("itemName", newItemName);
            itemIdRef.update(map);
        });

        builder.setNegativeButton("Delete", (dialogInterface, i) -> {
            itemIdRef.delete().addOnSuccessListener(aVoid -> Snackbar.make(shoppingListViewFragment, "Item deleted!", Snackbar.LENGTH_LONG).show());
        });

        AlertDialog alertDialog = builder.create();
        alertDialog.show();

        return true;
    });
}

运行应用程序时,在for循环“ for(Map.Entry entry:map1.entrySet())”的第61行发生致命错误

我从Android Studio IDE中收到以下错误

  

E / Android运行时:致命异常:主要                     流程:example.com.shoppinghelper,PID:17150                     java.lang.NullPointerException:尝试在null上调用接口方法'java.util.Set java.util.Map.entrySet()'   对象参考                         在example.com.shoppinghelper.shopping_container.ProductContainer.lambda $ null $ 0 $ ProductContainer(ProductContainer.java:61)                         在example.com.shoppinghelper.shopping_container.ProductContainer $$ Lambda $ 6.onComplete(未知   来源:0)                         在com.google.android.gms.tasks.zzf.run(未知来源:23)                         在android.os.Handler.handleCallback(Handler.java:789)                         在android.os.Handler.dispatchMessage(Handler.java:98)                         在android.os.Looper.loop(Looper.java:164)                         在android.app.ActivityThread.main(ActivityThread.java:6940)                         在java.lang.reflect.Method.invoke(本机方法)                         在com.android.internal.os.Zygote $ MethodAndArgsCaller.run(Zygote.java:327)                         在com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1374)

基本上,如果特定列表是由某人共享的,则代码尝试将数据存储到通知集合中。但是,如果没有人与我共享特定的购物清单,那么我将收到上述错误。

我关注的

视频教程是: https://www.youtube.com/watch?v=6RzB4HXzQyA&list=PLn2n4GESV0AmXOWOam729bC47v0d0Ohee&index=16

请帮助。 :)

1 个答案:

答案 0 :(得分:0)

您的map1对象获得了getResult()的值,但您会发现getResult()将返回null

NULL

这是出于声明

Map<String, Object> map1 = (Map<String, Object>) task.getResult().get("users");

要导致空指针异常,您应该在它之前添加一个检查map1!= null