如何在Excel中计算连续值?

时间:2018-10-06 00:20:26

标签: excel

此刻,我有一个计算连续值的公式:

=IF(AB5=0;0;IF(OR(AND(AB4>=100;AB5>=100);AND(AB4<=-100;AB5<=-100));AC4+1;1))

基本上是这样做的:

0           0
0           0
-110        1
-110        2
-110        3
-100        4
0           0
0           0
0           0
130         1
150         2
0           0
0           0
-100        1
0           0
0           0
0           0
0           0
-110        1
0           0
0           0
0           0
-220        1
-150        2
0           0
0           0

但是我希望它这样做:

0           0
0           0
-110        0
-110        0
-110        0
-100        4
0           0
0           0
0           0
130         0
150         2
0           0
0           0
-100        1
0           0
0           0
0           0
0           0
-110        1
0           0
0           0
0           0
-220        0
-150        2
0           0
0           0

或者这个:

0           0
0           0
-110        4
-110        0
-110        0
-100        0
0           0
0           0
0           0
130         2
150         0
0           0
0           0
-100        1
0           0
0           0
0           0
0           0
-110        1
0           0
0           0
0           0
-220        2
-150        0
0           0
0           0

要实现这一目标的公式是什么?

我希望不必添加更多列,因为文件已经很大...

仅使用公式即可做到这一点。

谢谢。

2 个答案:

答案 0 :(得分:2)

您可以尝试这样的匹配公式:

=IF(AND(ABS(AB5)>=100,AB4=0),MATCH(0,AB6:AB$1048576,0),0)

编辑

很明显,这对于1,000,000个细胞来说很慢。不完全匹配的速度更快:

=IF(AND(AB5>=100,AB4=0),MATCH(0,AB6:AB$1048576,-1),IF(AND(AB5<=-100,AB4=0),MATCH(-100,AB5:AB$1048576,1),0))

enter image description here

讨论

为什么Match从表面上看这么慢,它应该只在前面的几个单元格中寻找匹配项?我想知道是否是因为Match将要搜索的整个范围复制到一个临时数组?通常,这可能是一个不错的策略,但是在特定情况下,当匹配值接近范围的开始并且范围很大时,这是一个不好的策略。

另一种可能的方法是使用“频率”(最快)来确定最长的序列,然后使用“索引”来限制要搜索的范围,例如:

=MAX(FREQUENCY(IF(ABS(A:A)>=100,ROW(A:A)),IF(A:A=0,ROW(A:A))))
然后在B1中

...MATCH(0,AB6:INDEX(A:A,ROW()+B$1),0)

答案 1 :(得分:1)

连续计数版本1

我不知道如何使用excel解决您的问题,它可能可以通过一些数组公式来完成,这将极大地减慢您甚至现在很慢的工作簿的速度。因此,我写了一个VBA版本。
在使用它之前,应仔细更改第一个三个变量的值以适合您的需求。
将以下代码放入模块

Option Explicit
'-- Customize BEGIN --------------------

  'Read data from this column, and write to the next, e.g.
  'The AB column is column 28: Read from 28 and write to 29
  Public Const ciCol As Integer = 6

  'The first row of data
  Public Const cLoFirstRow As Long = 5

  'cLoRow is an approximate value e.g. you have 200 rows of data and you
  'estimate that you won't have more than a 1000 in a year, than 1000 is enough,
  'if you have a million then put in a million. The smaller this number the
  'faster the code.
  Public Const cLoRow As Long = 1000
'-- Customize END ----------------------

Sub ConsecutiveCounting1()
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
'-- Customize BEGIN --------------------
  'The Abs function eliminates the need for a negative value variable.
  Const cLoLimit As Long = 100
'-- Customize END ----------------------
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
  Dim oRng As Range
  Dim loLastRow As Long
  Dim loTemp As Long
  Dim loF1 As Long 'Row Counter
  loLastRow = Cells(Rows.Count, ciCol).End(xlUp).Row
  Set oRng = Range(Cells(cLoFirstRow, ciCol), Cells(loLastRow, ciCol))
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
  loTemp = 0
  For loF1 = 1 To oRng.Rows.Count
    If loF1 <> oRng.Rows.Count Then
      If Abs(oRng(loF1, 1)) >= cLoLimit Then
        loTemp = loTemp + 1
        If Abs(oRng(loF1 + 1, 1)) >= cLoLimit Then
          oRng(loF1, 2) = 0
         Else
          oRng(loF1, 2) = loTemp
          loTemp = 0
        End If
       Else
        oRng(loF1, 2) = 0
      End If
     Else 'Last Value
      If Abs(oRng(loF1, 1)) >= cLoLimit Then
        loTemp = loTemp + 1
        oRng(loF1, 2) = loTemp
       Else
        oRng(loF1, 2) = 0
      End If
    End If
  Next
End Sub

然后将以下代码放在工作表的代码窗口中:

Option Explicit
Private Sub Worksheet_Change(ByVal Target As Range)
  Dim ColumnNumber As Long
  Dim RowNumber As Long
    ColumnNumber = Target.Column
    RowNumber = Target.Row
    If ColumnNumber <> ciCol Then Exit Sub
    If RowNumber > cLoRow Then Exit Sub
  ConsecutiveCounting1
End Sub

代码会自动更改目标列中单元格的值,而结果单元格中没有任何公式,这应该使其变得非常快。如果不是这种情况,则可以编写一个数组版本,这会使代码快数十倍。