Question

我有一个像这样的数组：-

[Column(DbType="INT NOT NULL IDENTITY", IsPrimaryKey=true, IsDbGenerated=true)]
public int ID {get; set;}

我该如何进行循环，以便最后我得到一定数量的a而只有正数。

Answer 1

假设您的数组是这个，

$array = array(
    array('amount' => 3, 'address' => 'a'),
    array('amount' => 26, 'address' => 'a'),
    array('amount' => 345, 'address' => 'a'),
    array('amount' => -3, 'address' => 'a'),
    array('amount' => 22, 'address' => 'a'),    
);

您可以编写一个小的for循环来实现这一目标，

$results = array();
foreach ($array as $k => $v){   
    if($v['amount'] > 0 && $v['address'] == 'a'){           
        $results[] = $v;
    }   
}

print_r($results);

这将为您提供amount大于0且address为a的元素。这是您要找的吗？

Answer 2

请问您想要的东西更精确吗？

假设您的数组位于名为$ _var的var中。

foreach($_var as $_array){
  if($_array['amount'] > 0 && $_array['address']=='a'){ //if the amount is positiv and address = 'a'
    $res[] = $_array; //Push the current item in your res array
  }
}

$amount_of_a = count($res); //The number of a
print_r($res); //your result

通读循环并查找PHP

2 个答案: