Question

我有一个要求，我需要从给定日期动态返回月份。

例如，如果输入为libRNPurchases.a，则输出应为

2018-05-20

Answer 1

就我个人而言，我将使用统计表而不是rCTE。考虑到您只需要0-11，就可以轻松地“硬编码”值：

DECLARE @Date date = '20180520';

SELECT DATENAME(MONTH,DATEADD(MONTH, V.M, @Date))
FROM (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11)) V(M)
ORDER BY V.M;

Answer 2

您可以尝试使用cte递归。

开始日期是今天，结束日期是明年。

cte recursive条件是每增加一个月进行一次比较。

查询1 ：

;WITH CTE(startDt,endDt) AS (
   SELECT  CAST('2018-05-20' AS DATE) startDt, DATEADD (year,1,'2018-05-20') endDt
   UNION ALL
   SELECT DATEADD(month,1,startDt) ,endDt
   FROM CTE
   WHERE DATEADD(month,1,startDt) < endDt
)
SELECT datename(month, startDt)
FROM CTE

Results ：

|           |
|-----------|
|       May |
|      June |
|      July |
|    August |
| September |
|   October |
|  November |
|  December |
|   January |
|  February |
|     March |
|     April |

Answer 3

满足您的要求吗？

-- TEST DATA
declare @my_date as date = '2018-05-20';

-- SOLUTION
with cte as (
select DATENAME(month,@my_date) name, CAST(1 as int) lvl
union all 
select DATENAME(month,dateadd(month,cte.lvl,@my_date)),cte.lvl + 1 from cte where cte.lvl <12
)
select name as [Month Name] from cte;

Answer 4

您可以尝试以下方式

strdup

Answer 5

您也可以这样做

DECLARE @Date date = '20180520';

SELECT DATENAME(MONTH,DATEADD(MONTH, V.[Numbers], @Date)) AS Months
FROM (
SELECT  TOP (11 - 0+1) ROW_NUMBER() OVER (ORDER BY S.[object_id])+(0 - 1) [Numbers]
FROM    sys.all_objects S WITH (NOLOCK)
) V

动态显示给定日期的月份

5 个答案: