猪两台电脑游戏

Question

我有一个任务，我需要计算机自己玩猪游戏，一旦滚动100便停止。因此，我有两名计算机玩家并肩作战，但问题是，尽管这些玩家本来可以拥有100位玩家，但他们一直坚持到turntotal >= 20为止，这反过来又给了另一位玩家赢得胜利的机会，因为可以达到100的点。它在我们的任务中特别指出要注意这个问题，但是我不知道如何去解决这个问题。同样，使代码更简洁的任何方法也将有所帮助。

def playerOne(score):
    turntotal = 0
    scoretotal = 0
    while(scoretotal >= 0 and scoretotal <= 100):
        while(scoretotal < 100):
            roll = random.randint(1,6)
            print('Rolled a ', roll)
            if(turntotal <= 20 and roll != 1):
                turntotal = turntotal + roll
                scoretotal = scoretotal + roll
                if(turntotal >= 20):
                    break
            if(roll == 1):
                scoretotal = scoretotal - turntotal
                turntotal = 0
                print('Pigged Out!!!')
                break
        print('Turn score =', turntotal)
        turntotal = 0
        return scoretotal

def printScore():
    print(' ')
    print("Player One score is", PlayerOneScore)
    print("Player two score is", PlayerTwoScore)
    print(' ')

PlayerOneScore = 0
PlayerTwoScore = 0
flipcoin = random.randint(1,2)

if(flipcoin == 1):
    while(PlayerOneScore < 100 or PlayerTwoScore < 100):
        printScore()
        print("Player 1's turn")

        PlayerOneScore += playerOne(PlayerOneScore)
        if(PlayerOneScore >= 100):
            break

        printScore()
        print("Player 2's turn")    

        PlayerTwoScore += playerOne(PlayerTwoScore)
        if(PlayerTwoScore >= 100):
            break
else:
    while(PlayerOneScore < 100 or PlayerTwoScore < 100):
        printScore()
        print("Player 2's turn")    

        PlayerTwoScore += playerOne(PlayerTwoScore)
        if(PlayerTwoScore >= 100):
            break

        printScore()
        print("Player 1's turn")

        PlayerOneScore += playerOne(PlayerOneScore)
        if(PlayerOneScore >= 100):
            break

printScore()

if(PlayerTwoScore > PlayerOneScore):
    print("PLAYER 2 WINS")
else:
    print("PLAYER 1 WINS")