我正在尝试使用此post中的函数来生成小提琴分割图。
代码如下:
GeomSplitViolin <- ggproto("GeomSplitViolin", GeomViolin, draw_group = function(self, data, ..., draw_quantiles = NULL){
data <- transform(data, xminv = x - violinwidth * (x - xmin), xmaxv = x + violinwidth * (xmax - x))
grp <- data[1,'group']
newdata <- plyr::arrange(transform(data, x = if(grp%%2==1) xminv else xmaxv), if(grp%%2==1) y else -y)
newdata <- rbind(newdata[1, ], newdata, newdata[nrow(newdata), ], newdata[1, ])
newdata[c(1,nrow(newdata)-1,nrow(newdata)), 'x'] <- round(newdata[1, 'x'])
if (length(draw_quantiles) > 0 & !scales::zero_range(range(data$y))) {
stopifnot(all(draw_quantiles >= 0), all(draw_quantiles <=
1))
quantiles <- ggplot2:::create_quantile_segment_frame(data, draw_quantiles)
aesthetics <- data[rep(1, nrow(quantiles)), setdiff(names(data), c("x", "y")), drop = FALSE]
aesthetics$alpha <- rep(1, nrow(quantiles))
both <- cbind(quantiles, aesthetics)
quantile_grob <- GeomPath$draw_panel(both, ...)
ggplot2:::ggname("geom_split_violin", grid::grobTree(GeomPolygon$draw_panel(newdata, ...), quantile_grob))
}
else {
ggplot2:::ggname("geom_split_violin", GeomPolygon$draw_panel(newdata, ...))
}
})
geom_split_violin <- function (mapping = NULL, data = NULL, stat = "ydensity", position = "identity", ..., draw_quantiles = NULL, trim = TRUE, scale = "area", na.rm = FALSE, show.legend = NA, inherit.aes = TRUE) {
layer(data = data, mapping = mapping, stat = stat, geom = GeomSplitViolin, position = position, show.legend = show.legend, inherit.aes = inherit.aes, params = list(trim = trim, scale = scale, draw_quantiles = draw_quantiles, na.rm = na.rm, ...))
}
这是一个示例数据集:
set.seed(20160229)
my_data = data.frame(
y=c(rnorm(1000), rnorm(1000, 0.5), rnorm(1000, 1), rnorm(1000, 1.5)),
x=c(rep('a', 2000), rep('b', 2000)),
m=c(rep('i', 1000), rep('j', 2000), rep('i', 1000))
)
在绘图函数中使用aes()
,我们可以获得正常的绘图
ggplot(my_data, aes(x, y, fill=m)) + geom_split_violin()
但是如果使用aes_string()
,我会得到一个奇怪的图,其中两个分裂的小提琴彼此重叠。
ggplot(my_data, aes_string(x='x', y='y', fill='m')) + geom_split_violin()
我对aes
与aes_string
可能如何导致这种差异没有很好的理解。希望有人能给我提示。非常感谢!
答案 0 :(得分:1)
您可以在aes_string()
或更高版本中使用tidy evaluation方法,而不是使用ggplot2 3.0
:
使用sym()
使用aes()
在!!
中取消对它们的引用,以便对其进行评估
library(tidyverse)
ggplot(my_data, aes(x = !!sym('x'), y = !!sym('y'), fill = !!sym('m'))) + geom_split_violin()
由reprex package(v0.2.1.9000)于2018-10-04创建