Question

我正在尝试在头文件中创建参数化静态数组。让我详细说明我的要求

想在头文件中静态创建以下数组，可以在以下位置解析编译时间

static char test_array[][256] = {   
                              "hello_1",
                              "hello_2",
                              "hello_3" };

我需要使用宏生成此宏，该宏可以用％d代替1,2和3以及数字参数的值也不固定。我的意思是明天该数组可以简单地通过头文件更改为

static char test_array[][256] = {
                          "hello_1",
                          "hello_45",
                          "hello_39",
                          "hello_101" };

我有在运行时在.c文件中执行此操作的代码，但我想通过宏在头文件中进行操作。

Answer 1

最好的方法是编写生成器，它在编译时生成头数组。不久前，我编写了程序，可能会为您指明正确的方向：

/*
 * Copyright (c) 2018 Krzysztof "Palaiologos" Szewczyk
 *
 * Permission is hereby granted, free of charge, to any person obtaining a copy
 * of this software and associated documentation files (the "Software"), to
 * deal in the Software without restriction, including without limitation the
 * rights to use, copy, modify, merge, publish, distribute, sublicense, and/or
 * sell copies of the Software, and to permit persons to whom the Software is
 * furnished to do so, subject to the following conditions:
 *
 * The above copyright notice and this permission notice shall be included in
 * all copies or substantial portions of the Software.
 *
 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
 * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING
 * FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS
 * IN THE SOFTWARE.
 */

#include <stdlib.h>
#include <stdio.h>
#include <stdint.h>

#define PERLINE 30
#define BUFSIZE 1024

static const char hexrange[] = "0123456789ABCDEF";
char buf[BUFSIZE];
int lineidx,line,i,bytes;

int main(int argc, const char * argv[]) {
    FILE * in, * out;
    if (argc != 4) {
        fprintf(stderr, "Usage: %s infile outfile symbol\n", argv[0]);
        return 1;
    }
    in = fopen(argv[1], "rb");
    out = fopen(argv[2], "wb");
    if (!in || !out) {
        fputs("Could not open one of input files.\n", stderr);
        return 1;
    }
    fprintf(out, "/* Generated by HexExport (by Krzysztof Szewczyk a.k.a. Palaiologos) */\n\n");
    fprintf(out, "static const unsigned char %s[] = {", argv[3]);
    while ((bytes = fread(buf, 1, sizeof(buf), in)) > 0) {
        for (i = 0; i < bytes; ++i) {
            int byte = ((uint8_t *)buf) [i];
            if (lineidx++ == 0) {
                if (line++)
                    fputc(',', out);
                fputs("\n\t", out);
            } else
                fputs(", ", out);
            fputs("0x", out);
            fputc(hexrange[byte >> 4], out);
            fputc(hexrange[byte & 0xF], out);
            if (lineidx >= PERLINE)
                lineidx = 0;
        }
    }
    fputs("\n};\n", out);
    fclose(in);
    fclose(out);
    return 0;
}

它的作用很简单，就是从文件生成十六进制数组。您可以对其进行修改以完成您的任务。使用宏生成这样的数组是不可能或非常艰巨的任务。源代码取自this place

通过宏创建字符串数组的最佳方法

1 个答案: