Question

我有此数据：

let myInputArray = [
    {
        "id": 1,
        "commercialRanges": [
          {
            "rangeId": "305",
            "rangeName": "FIXE"
          },
          {
            "rangeId": "306",
            "rangeName": "POSTPAID"
          },
        ],
        "active": true,
        "pefName": "Alertes",
        "roles": "ADVISOR",
        "equipmentTypes": "PC",
      },
      ...
      {
        "id": 1523,
        "commercialRanges": [
          {
            "rangeId": "700",
            "rangeName": "POSTPAID"
          },
          {
            "rangeId": "500",
            "rangeName": "PREPAID"
          },
        ]
        ,
        "active": true,
        "pefName": "Alertes",
        "roles": "ADVISOR",
        "equipmentTypes": "PC",
      },
    ]

我想更新我的数据：从其格式（对象数组）转换属性“ commercialRanges” ->转换为简单的字符串：（其中连接了不同的“ rangeName ”值）

我得到的数组将是这样的：

myResultArray = [
{
    "id": 1,
    "commercialRanges": "FIXE,POSTPAID",
    "active": true,
    "pefName": "Alertes",
    "roles": "ADVISOR",
    "equipmentTypes": "PC",
  },
  ...
  {
    "id": 1523,
    "commercialRanges": "POSTPAID,PREPAID",
    "active": true,
    "pefName": "Alertes",
    "roles": "ADVISOR",
    "equipmentTypes": "PC",
  },
]

因此，我应该转换嵌入对象“ commercialRanges”

"commercialRanges": [
      {
        "rangeId": "305",
        "rangeName": "FIXE"
      },
      {
        "rangeId": "306",
        "rangeName": "POSTPAID"
      },
    ]

至：

"commercialRanges": "FIXE,POSTPAID"

Answer 1

您可以尝试使用Array.forEach，Array.map和Array.join

let myInputArray = [{"id":1,"commercialRanges":[{"rangeId":"305","rangeName":"FIXE"},{"rangeId":"306","rangeName":"POSTPAID"}],"active":true,"pefName":"Alertes","roles":"ADVISOR","equipmentTypes":"PC"}];
  
myInputArray.forEach(o => o.commercialRanges = o.commercialRanges.map(r => r.rangeName).join(','));
console.log(myInputArray);

Answer 2

基本思想是循环遍历myInputArray数组并将commercialRanges简化为字符串；为此，您还需要使用循环。

我建议您在Array.prototype.reduce上使用myInputArray方法，然后在Array.prototype.map数组上使用commercialRanges，因为这是最简单/最优雅的实现方式这个。您也可以将map和reduce用于两个循环。完全由您决定。这是我的去

let myInputArray = [
  {
      "id": 1,
      "commercialRanges": [
        {
          "rangeId": "305",
          "rangeName": "FIXE"
        },
        {
          "rangeId": "306",
          "rangeName": "POSTPAID"
        },
      ],
      "active": true,
      "pefName": "Alertes",
      "roles": "ADVISOR",
      "equipmentTypes": "PC",
    },
    ...
    {
      "id": 1523,
      "commercialRanges": [
        {
          "rangeId": "700",
          "rangeName": "POSTPAID"
        },
        {
          "rangeId": "500",
          "rangeName": "PREPAID"
        },
      ]
      ,
      "active": true,
      "pefName": "Alertes",
      "roles": "ADVISOR",
      "equipmentTypes": "PC",
    },
  ]

const myInputString = myInputArray.reduce((arr, obj) => [
  ...arr,
  {
    ...obj,
    commercialRanges: obj.commercialRanges.map(rObj => rObj.rangeName).join(',')
  }
], [])

选项2：用Array.prototype.map

循环这两个数组

const myInputString = myInputArray.map(obj => ({
    ...obj,
    commercialRanges: obj.commercialRanges.map(rObj => rObj.rangeName).join(',')
  })
)

映射对象属性并转换为字符串

2 个答案: