Java-使用两个对象之间的距离获取0-255之间的alpha值

时间:2018-10-04 07:04:08

标签: java colors alpha

我正在开发2D平台游戏。背景中有star个对象,这些星星在四处移动。我想在它们之间画线,并且我已经做了很多努力。我现在想做的是在绘制的线条上添加一个alpha值(透明度)。 我试图写一个方程,其中alpha值与两个对象之间的距离值成反比,但没有成功。

如何数学表达以下规则?

  

距离越大,alpha值越小

例如,如果 distance 400,则透明度值应为0(java.awt.Color使用0作为100%透明度,使用255作为无透明度)


这是我要实现的目标的一个示例:

var canvas = document.getElementById("canvas"),
    ctx = canvas.getContext('2d');

canvas.width = window.innerWidth;
canvas.height = window.innerHeight;

var stars = [], // Array that contains the stars
    FPS = 60, // Frames per second
    x = 40, // Number of stars
    mouse = {
      x: 0,
      y: 0
    };  // mouse location

// Push stars to the array

for (var i = 0; i < x; i++) {
  stars.push({
    x: Math.random() * canvas.width,
    y: Math.random() * canvas.height,
    radius: Math.random() * 1 + 1,
    vx: Math.floor(Math.random() * 50) - 25,
    vy: Math.floor(Math.random() * 50) - 25
  });
}

// Draw the scene

function draw() {
  ctx.clearRect(0,0,canvas.width,canvas.height);
  
  ctx.globalCompositeOperation = "lighter";
  
  for (var i = 0, x = stars.length; i < x; i++) {
    var s = stars[i];
  
    ctx.fillStyle = "#fff";
    ctx.beginPath();
    ctx.arc(s.x, s.y, s.radius, 0, 2 * Math.PI);
    ctx.fill();
    ctx.fillStyle = 'black';
    ctx.stroke();
  }
  
  ctx.beginPath();
  for (var i = 0, x = stars.length; i < x; i++) {
    var starI = stars[i];
    ctx.moveTo(starI.x,starI.y); 
    if(distance(mouse, starI) < 150) ctx.lineTo(mouse.x, mouse.y);
    for (var j = 0, x = stars.length; j < x; j++) {
      var starII = stars[j];
      if(distance(starI, starII) < 150) {
        //ctx.globalAlpha = (1 / 150 * distance(starI, starII).toFixed(1));
        ctx.lineTo(starII.x,starII.y); 
      }
    }
  }
  ctx.lineWidth = 0.05;
  ctx.strokeStyle = 'white';
  ctx.stroke();
}

function distance( point1, point2 ){
  var xs = 0;
  var ys = 0;
 
  xs = point2.x - point1.x;
  xs = xs * xs;
 
  ys = point2.y - point1.y;
  ys = ys * ys;
 
  return Math.sqrt( xs + ys );
}

// Update star locations

function update() {
  for (var i = 0, x = stars.length; i < x; i++) {
    var s = stars[i];
  
    s.x += s.vx / FPS;
    s.y += s.vy / FPS;
    
    if (s.x < 0 || s.x > canvas.width) s.vx = -s.vx;
    if (s.y < 0 || s.y > canvas.height) s.vy = -s.vy;
  }
}

canvas.addEventListener('mousemove', function(e){
  mouse.x = e.clientX;
  mouse.y = e.clientY;
});

// Update and draw

function tick() {
  draw();
  update();
  requestAnimationFrame(tick);
}

tick();
canvas {
  background: #232323;
}
<canvas id="canvas"></canvas>

1 个答案:

答案 0 :(得分:2)

您应该使用:

((MAX_DISTANCE - distance) / MAX_DISTANCE) * 255

说明:
(MAX_DISTANCE - distance)确保距离较大,结果较小
然后,乘以MAX_DISTANCE乘以255,将其从0-MAX_DISTANCE缩放为0-255。