所以我有三个具有相同轮播效果的DIV。我敢肯定,我可以使用三种不同的JavaScript代码来一次移动一个,但是希望尽可能地减少代码。使用当前代码,当我单击箭头一次时,它们全部三个都移动了。如何让他们分开移动?
与下面的三个相同:
(function ($) {
$.fn.thumbGallery = function (settings) {
var $this = $(this);
return this.each(function () {
settings = jQuery.extend({
speed: 1000,
leftArrow: $this.find('.arrow-left'),
rightArrow: $this.find('.arrow-right'),
galleryContainer: $this.find('.gallery-inner'),
visibleImagesSize: 4
}, settings);
var imgElements = settings.galleryContainer.find('img').length;
var size = settings.visibleImagesSize;
//settings.leftArrow.hide();
if (imgElements > settings.visibleImagesSize) {
settings.rightArrow.show();
} else {
//settings.rightArrow.hide();
}
function animateLeft() {
var el = settings.galleryContainer.children(":last");
settings.galleryContainer.animate({
left: '+=' + el.outerWidth(true) + 'px'
},
settings.speed);
}
function animateRight() {
var el = settings.galleryContainer.children(":first");
settings.galleryContainer.animate({
left: '-=' + el.outerWidth(true) + 'px'
},
settings.speed);
}
function checkArrows() {
if (size === settings.visibleImagesSize) {
//settings.leftArrow.hide();
} else {
settings.leftArrow.show();
}
if (size === imgElements) {
//settings.rightArrow.hide();
} else {
settings.rightArrow.show();
}
}
settings.leftArrow.click(function () {
animateLeft();
size--;
checkArrows();
});
settings.rightArrow.click(function () {
animateRight();
size++;
checkArrows();
});
});
};
})(jQuery);
$(document).ready(function () {
$('.gallery').thumbGallery();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="open-space">
<h2>Open Space</h2>
<p class="description">Desk space in an open shared office environment that can be used in various of ways.</p>
<center>
<div class="gallery">
<div class="arrow-left">
<div class="arrow-left-small">
</div>
</div>
<div class="gallery-outer">
<div class="gallery-inner">
<div class="gallery-tmb">
<img src="images/openspace1.png" alt="Open Space1" height="auto" width="250"/>
</div>
<div class="gallery-tmb">
<img src="images/openspace2.png" alt="Open Space2" height="auto" width="250"/>
</div>
<div class="gallery-tmb">
<img src="images/openspace3.png" alt="Open Space3" height="auto" width="250"/>
</div>
<div class="gallery-tmb">
<img src="images/openspace4.png" alt="Open Space4" height="auto" width="250"/>
</div>
<div class="gallery-tmb">
<img src="images/openspace5.png" alt="Open Space5" height="auto" width="250"/>
</div>
<div class="gallery-tmb">
<img src="images/openspace6.png" alt="Open Space6" height="auto" width="250"/>
</div>
</div>
</div>
<div class="arrow-right">
<div class="arrow-right-small">
</div>
</div>
</div>
<span class="btn_margin">
<asp:Button ID="Button3" runat="server" Text="More lists" CssClass="btn btn-primary top" OnClick="Btn_More_Click" />
</span>
</center>
</div>
答案 0 :(得分:2)
它们一起移动的原因是因为在调用.gallery
时使用了thumbsGallery()
选择器,该选择器适用于HTML代码中具有class="gallery"
的所有元素。您可以做的就是简单地向每个图库添加唯一的id
并使用每个选择器调用thumbsGallery()
。
HTML:
<div class="gallery" id="executive_gallery">
...
</div>
<div class="gallery" id="conference_gallery">
...
</div>
<div class="gallery" id="open_gallery">
...
</div>
Javascript:
$(document).ready(function () {
$('.gallery#executive_gallery').thumbGallery();
$('.gallery#conference_gallery').thumbGallery();
$('.gallery#open_gallery').thumbGallery();
});
JSFiddle:https://jsfiddle.net/3qeLumkp/1/