我正在从本书中以母语学习Spring MVC。
是时候使用Spring Security了。我已经复制了本书中的所有内容。不幸的是,结果我收到了很多错误。在添加之前一切正常。我认为security-context.xml
引起了问题,因为未使用照片上的链接。我正在使用IntelliJ。
这是我的 pom.xml
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.packt</groupId>
<artifactId>webstore</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>war</packaging>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>5.0.8.RELEASE</version>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
<version>1.2</version>
</dependency>
<dependency>
<groupId>org.springframework.security</groupId>
<artifactId>spring-security-config</artifactId>
<version>5.0.6.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework.security</groupId>
<artifactId>spring-security-web</artifactId>
<version>5.0.6.RELEASE</version>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>javax.servlet-api</artifactId>
<version>3.1.0</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>jstl</groupId>
<artifactId>jstl</artifactId>
<version>1.2</version>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>1.8</source>
<target>1.8</target>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-war-plugin</artifactId>
<version>2.6</version>
<configuration>
<warSourceDirectory>webapp</warSourceDirectory>
<failOnMissingWebXml>false</failOnMissingWebXml>
</configuration>
</plugin>
</plugins>
</build>
</project>
security-conext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/springsecurity-3.1.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/springcontext-3.2.xsd">
<security:http auto-config="true">
<security:intercept-url pattern="/products/add" access="ROLE_ADMIN"/>
<security:form-login login-page="/login" default-target-url="/products/add"
authentication-failure-url="/loginfailed"/>
<security:logout logout-success-url="/logout"/>
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:user-service>
<security:user name="Admin" password="Admin123" authorities="ROLE_ADMIN"/>
</security:user-service>
</security:authentication-provider>
</security:authentication-manager>
</beans>
web.xml
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring/webcontext/security-context.xml
</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>DefaultServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/webcontext/DispatcherServlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>DefaultServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
login.jsp
在这里我遇到了<form action="<c:url value="/j_spring_security_check"></c:url>" method="post">
的错误。它说Cannot resolve controller URL '/j_spring_security_check'
<%@page pageEncoding="UTF-8" contentType="text/html; charset=UTF-8" %>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form" %>
<%@ taglib prefix="spring" uri="http://www.springframework.org/tags" %>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<link rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.0.0/css/bootstrap.min.css">
<title>Produkty</title>
</head>
<body>
<section>
<div class="jumbotron">
<div class="container">
<h1>Produkty</h1>
<p>Dodaj produkty</p>
</div>
</div>
</section>
<div class="container">
<div class="row">
<div class="col-md-4 col-md-offset-4">
<div class="panel panel-default">
<div class="panel-heading">
<h3 class="panel-title">Zaloguj się</h3>
</div>
<div class="panel-body">
<c:if test="${not empty error}">
<div class="alert alert-danger">
<spring:message code="AbstractUserDetailsAuthenticationProvider.badCredentials"/><br/>
</div>
</c:if>
<form action="<c:url value="/j_spring_security_check"></c:url>" method="post">
<fieldset>
<div class="form-group">
<input class="form-control" placeholder="Nazwa użytkownika" name='j_username' type="text">
</div>
<div class="form-group">
<input class="form-control" placeholder="Hasło" name='j_password' type="password" value="">
</div>
<input class="btn btn-lg btn-success btn-block" type="submit" value="Zaloguj się">
</fieldset>
</form>
</div>
</div>
</div>
</div>
</div>
</body>
</html>
LoginController
package com.packt.webstore.controller;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
public class LoginController {
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String login() {
return "login";
}
@RequestMapping(value = "/loginfailed", method = RequestMethod.GET)
public String loginerror(Model model) {
model.addAttribute("error", "true");
return "login";
}
@RequestMapping(value = "/logout", method = RequestMethod.GET)
public String logout(Model model) {
return "login";
}
}
这是stacktrace: https://pastebin.com/P97E90Ra
我无法在此处添加内容,因为它太长了。
答案 0 :(得分:0)
spring安全模式URL不正确:
http://www.springframework.org/schema/security/springsecurity-3.1.xsd
https://www.springframework.org/security/spring-security-3.1.xsd
如果您尝试通过浏览器访问第一个(http://www.springframework.org/schema/security/springsecurity-3.1.xsd),则会得到一个404
。
第二个将为您正确地提供架构(https://www.springframework.org/security/spring-security-3.1.xsd)。
通常,请检查您已配置的所有资源URL(我可能不会在此处列出所有资源URL,因为它可能是一长串的列表,但这是相同的原理)