我正在尝试在具有另一列的列上使用like
函数。可以在like函数中使用Column
吗?
示例代码:
df['col1'].like(concat('%',df2['col2'], '%'))
错误日志:
py4j.Py4JException: Method like([class org.apache.spark.sql.Column]) does not exist
at py4j.reflection.ReflectionEngine.getMethod(ReflectionEngine.java:318)
at py4j.reflection.ReflectionEngine.getMethod(ReflectionEngine.java:326)
at py4j.Gateway.invoke(Gateway.java:274)
at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:214)
at java.lang.Thread.run(Thread.java:748)
答案 0 :(得分:2)
您可以使用SQL表达式来代替。由于某种原因,python API不直接支持它。例如:
from pyspark.sql.functions import expr
data = [
("aaaa", "aa"),
("bbbb", "cc")
]
df = sc.parallelize(data).toDF(["value", "pattern"])
df = df.withColumn("match", expr("value like concat('%', pattern, '%')"))
df.show()
输出以下内容:
+-----+-------+-----+
|value|pattern|match|
+-----+-------+-----+
| aaaa| aa| true|
| bbbb| cc|false|
+-----+-------+-----+