Python逻辑如果和或相反

Question

Level = 4
Name = "Mike"
Form = None
if Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form):

上面的代码完全可以实现我想要的功能，但是我不知道该怎么做：

例如

if Level != 5 and Name not in ['James','Chris','Alex'] and (Name not in ['John','Mike'] and Form):

与我接近，但无法正常工作。

Answer 1

如何将所有内容括在括号中，并在开始时只使用not。这样，您无需反转任何运算符。

if not (Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form)):

Answer 2

您的问题有点含糊，据我了解，这应该很简单，

if not (Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form)):

另一种简单的方法是做这样的事情

if Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form):
    pass
else:
    # your code here