Slim尊重验证问题

时间:2018-10-03 10:23:00

标签: php slim slim-3

Respect \ Validation \ Validator。我有一个验证器课程 validator.php

<?php

namespace app\http\validations;
use Respect\Validation\Validator as Respect;
use Respect\Validation\Exceptins\NestedValidationException;

class Validator {

    protected $errors = [];
    public function validate($request, array $rules){
        foreach ($rules as $field => $rule) {
            try{
               $rule->setName(ucfirst($field))->assert($request->getParam($field)); 
            } catch (NestedValidationException $ex) {
                $this->errors[$field] = $ex->getMessages();
            }

        }
        return $this;
    }

    public function failed(){
        return !empty($this->errors);
    }
}

然后我在控制器中使用此验证,这是我的控制器:

<?php

namespace app\http\controllers\v1;


use Slim\Http\Request;
use Slim\Http\Response;
use Respect\Validation\Validator as v;

use app\providers\v1\CompanyServiceProvider;

class CompanyController extends BaseApiController {

    public $companyServiceProvider;

    public function __construct() {
        $this->companyServiceProvider = new CompanyServiceProvider();
    }

    public function saveBasicDetails(Request $request, Response $response) {
        $validator = new \app\http\validations\Validator();
        $validation = $validator->validate($request, [
            'company_name' => v::notEmpty()->alpha()
         ]);

        if($validation->failed()){
            print_r($validation); die;
        }

        $result = $this->companyServiceProvider->saveBasicDetails($request);
        return BaseApiController::returnResponse($response, $result);
    }

}

这是我的路线,我正在从该路线调用saveBasicDetails函数。

$app->post('/save-basic-details', \app\http\controllers\v1\CompanyController::class. ':saveBasicDetails');

我遇到以下错误:这些规则必须通过Company_name

我想返回JSON中的验证错误。

2 个答案:

答案 0 :(得分:1)

在控制器中,您必须将容器注入构造函数中,然后定义一个getter来获取验证器。检查一下link,到目前为止,没有什么像symfony autowire一样必须显式注入容器并获得所需的服务的。在下面检查此代码将对您有帮助!

//use Psr\Container\ContainerInterface;


/**
 * @param ContainerInterface $container
 */
public function __construct(ContainerInterface $container)
{
    $this->container = $container;
}


//Then define a getter

/**
 * @return Validator
 */
protected function getValidator()
{
    if (!$this->validator instanceof Validator) {
        $this->validator = $this->container->get('Validator');
    }

    return $this->validator;
}


//Then access the validator
$this->getValidator()->validate...

答案 1 :(得分:0)

伙计们我犯了一个愚蠢的错误,其中有一个拼写错误

use Respect\Validation\Exceptins\NestedValidationException;

更改为

use Respect\Validation\Exceptions\NestedValidationException;

解决了我的问题。