Question

输入文字：Engineering School, Medical school, The School of Science, High School of science

要求的输出：[X] school, [X] school, The School of [X], High School of [X]

规则：school of或（不区分大小写）或School（不区分大小写）短语之前的任何单词都需要替换为[X]。但是，这两个规则不应同时执行。

$inputext = "Engineering School, Medical school, The School of Science"; 
$rule ="/\w+(?= school)/i";
$replacetext = "[X]";
$outputext = preg_replace($rule, $replacetext, $inputext);
echo($outputext);

说明清楚 -应该基于“学校”和“学校”（都不区分大小写）的出现来触发规则。 -如果存在“学校”，则不应触发“学校”规则

谢谢您的建议。

Answer 1

这将用school of ...替换school of [X]，并用... school替换[X] shool，除非后面跟随of

$inputext = "Queen's School, Engineering School, Medical school, The School of Science, High School of science the school is closed"; 
$rule = "/\b(?!the school is)(?:(?<=\bschool of )\S+|\S+(?= school\b(?! of)))/i";

$replacetext = "[X]";
$outputext = preg_replace($rule, $replacetext, $inputext);
echo $outputext,"\n";

输出：

[X] School, [X] School, [X] school, The School of [X] High School of [X] the school is closed

Answer 2

您可以使用基于环视的正则表达式进行搜索：

.*\K(?>(?<=school of )\w+|\b\w++(?= school))

替换为：

[X]

RegEx Demo

PHP代码：

$re = '/.*\K(?>(?<=school of )\w+|\b\w++(?= school))/';
$repl = preg_replace($re, '[X]', $str);

RegEx详细信息：

.*\K：首先匹配0个或更多字符，然后重置匹配信息
(?>：开始原子组
- (?<=school of )\w+：匹配以"school of "结尾的完整单词
- |：或
- \b\w++(?= school)：匹配完整的单词，后跟" school"
)：终止原子团

是否可以在PHP中使用正则表达式根据条件替换单词（之前或之后）？

2 个答案: