Question

我有一个包含重复项的整数列表。示例：

37 1 30 38 5 39 5 5 5 40 33 5 35 42 25 36 27 27 43 27

我需要将重复的号码更改为其他一些号码，如果它们不相继出现。新数字不应与列表中的其他数字重复。例如，上面的列表应如下所示：

37 1 30 38 5 39 8 8 8 40 33 2 35 42 25 36 27 27 43 55

这就是我得到的：

a = [37, 1, 30, 38, 5, 39, 5, 5, 5, 40, 33, 5, 35, 42, 25, 36, 27, 27, 43, 27]

duplicates = list(item for item, count in Counter(a).items() if count > 1)


for dup in duplicates:
    positions = []

    for item in range(len(a)):
        if a[item] == dup:
            positions.append(item)

    for x in range(len(positions)-1):
        if positions[x+1] - positions[x] != 1:
            ran = random.randrange(1, len(a))
            while ran in a:
                ran = random.randrange(1, len(a))
            a[positions[x+1]] = ran
        else:
            y = x
            while positions[y+1] - positions[y] == 1:
                a[positions[y+1]] = a[positions[y]]
                y += 1

[37，1，30，38， 5 ，39， 17 ， 17 ， 17 ， 40、33， 13 ，35、42、25、36， 27 ， 27 ， 43， 8 ]

但是我认为这不是一个好的解决方案。

Answer 1

您可以使用itertools.groupby以相同编号的块处理列表，并使用带有itertools.count的生成器表达式生成替换编号：

input_list = [37, 1, 30, 38, 5, 39, 5, 5, 5, 40, 33, 5, 35, 42, 25, 36, 27, 27, 43, 27]

import itertools

# make a generator that yields unused numbers
input_values = set(input_list)
unused_number = (num for num in itertools.count() if num not in input_values)

# loop over the input, grouping repeated numbers, and keeping track
# of numbers we've already seen
result = []
seen = set()
for value, group in itertools.groupby(input_list):
    # if this number has occurred already, pick a new number
    if value in seen:
        value = next(unused_number)

    # remember that we've seen this number already so future
    # occurrences will be replaced
    seen.add(value)

    # for each repeated number in this group, add the number
    # to the output one more time
    for _ in group:
        result.append(value)

print(result)
# output:
# [37, 1, 30, 38, 5, 39, 0, 0, 0, 40, 33, 2, 35, 42, 25, 36, 27, 27, 43, 3]

Answer 2

只是另一种方法。

演示：

import random


L = [37, 1, 30, 38, 5, 39, 5, 5, 5, 40, 33, 5, 35, 42, 25, 36, 27, 27, 43, 27]
result = []
previous_value = ''
dup_val = ''
length = len(L)
ran = ''

for i, v in enumerate(L):                              #Iterate Each element with index. 
    if (v not in result) or (v == previous_value):     #Check if value in result or previous value is the same. 
        result.append(v)
        previous_value = v
        dup_val = ''
    else:
        if dup_val == v:                                #Check if previous value is duplicate
            result.append(ran)
            continue
        else:
            ran = random.randrange(1, length)
            while ran in result:
                ran = random.randrange(1, length)
            result.append(ran)
            dup_val = v

print(result)

输出：

[37, 1, 30, 38, 5, 39, 16, 16, 16, 40, 33, 17, 35, 42, 25, 36, 27, 27, 43, 2]

如果不重复，请更改重复的列表项

2 个答案: