Question

我有以下实体

    @Entity
    @Table(name = "person")
    public class Person implements Serializable {

        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        @Column(name = "id")
        private Long id;

        // Other fields 
    }

     @Entity
        @Table(name = "agreement")
        public class Agreement implements Serializable {

            private static final long serialVersionUID = 15L;

            @Id
            @GeneratedValue(strategy = GenerationType.IDENTITY)
            @Column(name = "id")
            private Long id;

            @ManyToOne
            @JoinColumn(name = "person_id", nullable = false)
            private Person person;

            @ManyToOne
            @JoinColumn(name = "company_id", nullable = false)
            private Company company;

        }

    @Entity
    @Table(name = "company")
    public class Company implements Serializable {

        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        @Column(name = "id")
        private Long id;

        @Column(name = "name", length = 100)
        private String name;
    }

我需要让所有与该公司达成协议且公司ID为45的人员。以下是我为获取详细信息而编写的本机查询。

SELECT distinct p.* ROM person p INNER JOIN agreement a ON a.person_id = p.id where a.company_id = 45;

但是我被告知将其转换为JPA实体查询。我想出了以下内容，

SELECT distinct p  FROM Person p INNER JOIN Agreement a WHERE a.person = p AND a.company.id = 45;

但这给了我以下例外，

由于：org.hibernate.hql.internal.ast.QuerySyntaxException：路径期待加入！ [从人p INNER JOIN中选择不同的p 在以下位置同意a.person = p AND a.company.id = 45] org.hibernate.hql.internal.ast.QuerySyntaxException.convert（QuerySyntaxException.java:74）在 org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException（ErrorCounter.java:91）在 org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze（QueryTranslatorImpl.java:268）在 org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile（QueryTranslatorImpl.java:190）在 org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile（QueryTranslatorImpl.java:142）在 org.hibernate.engine.query.spi.HQLQueryPlan。（HQLQueryPlan.java:115）在 org.hibernate.engine.query.spi.HQLQueryPlan。（HQLQueryPlan.java:76）在 org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan（QueryPlanCache.java:150）在 org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan（AbstractSessionImpl.java:302）在 org.hibernate.internal.AbstractSessionImpl.createQuery（AbstractSessionImpl.java:240）在 org.hibernate.internal.SessionImpl.createQuery（SessionImpl.java:1894）在 org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery（AbstractEntityManagerImpl.java:305

有人可以帮我解决我在查询中做错了什么吗？

Answer 1

JPA使用HQL语句中的路径将一个实体与另一个实体相关联，因为它没有找到它要抱怨的实体。您可以尝试以下查询。

SELECT distinct p FROM Agreement a JOIN a.person p WHERE a.company.id = 45;

Hiberante内部连接提供了“连接预期路径”例外

1 个答案: