Question

我从命令中得到以下输出：

 24936 09/23/18 23:19:53 --------------------------------------------------
 24936 09/23/18 23:19:53                INITIALISING NETWORK PARAMETERS
 24936 09/23/18 23:19:53 --------------------------------------------------
 24936 09/23/18 23:19:53 Current Executable directory is C:\CVS\Base
 24936 09/23/18 23:19:53 Checking dBaseHome in the Registry for Instance002
 24936 09/23/18 23:19:53 C:\CVS\Base
 24936 09/23/18 23:19:53      Network Parameters
 24936 09/23/18 23:19:53     --------------------
 24936 09/23/18 23:19:53 Host Name              : 10-43-96-175
 24936 09/23/18 23:19:53 Domain Name            : abcd.com
 24936 09/23/18 23:19:53 DNS Server IP          : 12.43.53.23
 24936 09/23/18 23:19:53 Machine uses Dynamic Host configuration Protocol
 24936 09/23/18 23:19:53 No of Interfaces : 22
 24936 09/23/18 23:19:53  Initialization Completed
 --------------------------------------------------
                Initialization Result
--------------------------------------------------
Client Host Names               :lkmn.com
Client Names                    :client
CommServeHostName               :host.com
Configuration                   :The machine is Client
IP Configured                   :IPv4
Instance Name                   :Instance002
Networking Status               :Passed
--------------------------------------------------
                    LOG BEGINS
--------------------------------------------------
24936 09/23/18 23:19:53 --------------------------------------------------
 24936 09/23/18 23:19:53  DNS lookup for Host Name : abcd.com
 24936 09/23/18 23:19:53 --------------------------------------------------
 24936 09/23/18 23:19:53 DNS Look Up Output:
 Non-authoritative answer:
Server:  server.com
Address:  43.4.3.4

Name:    client.com
Address:  10.43.96.175

 24936 09/23/18 23:19:53 --------------------------------------------------
 24936 09/23/18 23:19:53 --------------------------------------------------
 24936 09/23/18 23:19:53 Using IPv4 family
 24936 09/23/18 23:19:53 Testing Addresses:
 24936 09/23/18 23:19:53 Testing 10.43.96.175 ->
 24936 09/23/18 23:19:53 [Failed]

 Failure reason : Generic Failure
--------------------------------------------------
                 SUMMARY
 --------------------------------------------------
 Forward and Reverse Lookup - CVIPInfo :

 IP : 10.43.96.175 Failed
 --------------------------------------------------
                    LOG ENDS
--------------------------------------------------

       RESULTS
       -------
 DNS LOOKUP       : SUCCESS
 HOST FILE LOOKUP : NOT PRESENT

 FORWARD AND REVERSE LOOKUP
 --------------------------
 IP Version : IPv4
 Status     : FAILED
____________________________________________________________
                           END
____________________________________________________________

我想从中提取密钥CommServeHostName的值host.com。

我尝试通过拆分行来遵循以下代码：

for (String line : output.split("\n")) {
  if (line.startsWith("CommServeHostName")) {
    String[] split = line.split(":");
    System.out.println(split.length > 1 ? split[1] : null);
    break;
  }
}

有没有一种更好的方法，而无需将输出拆分为行并使用正则表达式？必须使用Java-6完成。

Answer 1

您可以使用正则表达式

(?m)^CommServeHostName\\s+(.+)$

将与以CommServeHostName开头的行匹配，并在第一个捕获组的行末之前捕获所有非空格：

String reg = "(?m)^CommServeHostName\\s+(.+)$";
Matcher m = Pattern.compile(reg).matcher(output);
m.find();
System.out.println(m.group(1));

Answer 2

尝试检查匹配的行，然后提取所需的部分：

if (line.matches("CommServeHostName\\s+:.*")) {
    String value = line.replaceAll("^.*:", "");
    System.out.println(value);
}

用正则表达式代替字符串处理

2 个答案: