我在文件中具有以下struct
定义:
template <class... EventArgs>
struct banana {
template <class... Args>
void operator()(Args&&... args) const {
_f(std::forward<Args>(args)...);
}
private:
std::function<void(EventArgs...)> _f;
};
使用-ast-dump -fsyntax-only
,我可以清楚地看到转储中引用了CXXRecordDecl
的多个banana
和引用了CXXMethodDecl
的{{1}} :
operator()
我的`-ClassTemplateDecl 0x7fb23c11e028 <./test_files/templates.cpp:12:1, line:21:1> line:13:8 banana
|-TemplateTypeParmDecl 0x7fb23c11df08 <line:12:11, col:20> col:20 referenced class depth 0 index 0 ... EventArgs
|-CXXRecordDecl 0x7fb23c11df90 <line:13:1, line:21:1> line:13:8 struct banana definition
| |-CXXRecordDecl 0x7fb23c11e300 <line:13:1, col:8> col:8 implicit struct banana
| |-FunctionTemplateDecl 0x7fb23c11e668 <line:14:5, line:17:5> line:15:10 operator()
| | |-TemplateTypeParmDecl 0x7fb23c11e398 <line:14:15, col:24> col:24 referenced class depth 1 index 0 ... Args
| | `-CXXMethodDecl 0x7fb23c11e5d0 <line:15:5, line:17:5> line:15:10 operator() 'void (Args &&...) const'
| | etc., etc.
子类正在MatchFinder::MatchCallback
上运行以进行事件,但是CXXRecordDecl
返回的范围是空的:
methods()
我想念什么?
答案 0 :(得分:1)
好吧,clas->methods()
只返回CXXMethodDecl
顶层的struct
。
但是在您的struct
中,只有FunctionTemplateDecl
。
因此,您可能想要执行以下操作:
for (const auto &decl : clas->decls()) {
if (auto *templ = dyn_cast<FunctionTemplateDecl>(&decl)) {
// Use templ->getTemplatedDecl to get FunctionDecl.
}
}
注意。我尚未实际测试或编译该代码,但希望您能从中得到启发。