Question

在用户输入时，我很难打印第二个列表。仅打印第一个列表。另外，我不确定如何交换列表值然后打印它们。我的老师希望我们弄清楚如何在不编写函数的情况下做到这一点，但我不明白如何做到这一点。到目前为止，这是我的代码

#include<stdio.h>
int main()
{
int List1[5], List2[5];
int i, j;

printf("Please enter the values to List1 array\n ");
for (i = 0; i < 5; i++)
{
    scanf_s("%d", &List1[i]);
}

printf("Please enter the values to List2 array\n");
for (j = 0; j < 5; j++);
{
    scanf_s("%d", &List2[j]);
}

printf("List1 and List2 before swap\n");

printf("\nList1\t\t List 2\n");
for (int i = 0; i < 5; i++)
{
    printf("%d\n", List1[i]);
}

for (j = 0; j < 5; j++);
{
    printf("%d\n", List2[j]);
}


 //??? put something here to swap the elements and 

printf("\nList1 and List2 after swap");



return 0;
}

Answer 1

这些不是链表，它们只是int向量，如果要交换两个链表，则代码如下：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct Structure
{
  int n;
};

struct StructureNode
{
  struct Structure structure;
  struct StructureNode * next;
};

typedef struct StructureNode * Node;

void NewNode(struct Structure s, Node * p )
{
  Node temp;

  temp = (Node)malloc(sizeof(struct StructureNode));

  temp->structure = s;

  temp->next = *p;

  *p = temp;
}

void Read(struct Structure * p)
{
  printf("Insert a number in the list:");
  scanf("%d", &p->n);
}

void ViewLists(Node head1, Node head2)
{
  printf("List1:\n");
  while(head1 != NULL)
  {
    printf("%d\n", head1->structure.n);
    head1 = head1->next;
  }
  printf("List2:\n");
  while(head2 != NULL)
  {
    printf("%d\n", head2->structure.n);
    head2 = head2->next;
  }
}

void SwapLists(Node  head1, Node  head2)
{
  struct Structure temp;
  while(head1 != NULL && head2 != NULL)
  {
    temp = head1->structure;
    head1->structure = head2->structure;
    head2->structure = temp;

    head1 = head1->next;
    head2 = head2->next;
  }
}

int Menu()
{
  int c;
  printf("\nHow to swap two linked list by St3veR0nix\n"
        "\n1) Insert a value in List1\n"
        "\n2) Insert a value in List2\n"
        "\n3) Swap the lists\n"
        "\n4) Print both lists\n"
        "\n>>");
  scanf("%d", &c);
  return c;
}

int main()
{
  Node head1 = NULL;
  Node head2 = NULL;
  struct Structure s;
  int c;
  do {
    c = Menu();
    switch(c)
    {
      case 1: Read(&s);
              NewNode(s, &head1);
              break;
      case 2: Read(&s);
              NewNode(s, &head2);
              break;
      case 3: SwapLists(head1, head2);
              break;
      case 4: ViewLists(head1, head2);
              break;
      default: c = 0;
    }
  } while(c != 0);

}

Answer 2

您的代码@ RTR81中只有一个明显的错误。您用于for数组的List2循环，即j循环在for语句的末尾有一个分号。这导致循环甚至在移至第二个迭代之前就结束了。只需删除最后的分号（;），便可以读取整个输入数组。

for (j = 0; j < 5; j++);   //this semicolon needs to be removed.

现在进入交换部分。这是一个非常简单的伙伴。声明另一个变量，例如temp，首先将List1元素的值放入其中，然后将List2元素的值放入其中。然后将temp的值放入List2元素中。

我在下面发布了代码：

#include<stdio.h>
int main()
{
int List1[5], List2[5];
int i, j, temp;

printf("Please enter the values to List1 array\n ");
for (i = 0; i < 5; i++)
{
    scanf("%d", &List1[i]);
}

printf("Please enter the values to List2 array\n");
for (j = 0; j < 5; j++)//removed the semicolon here
{
    scanf("%d", &List2[j]);
}

printf("List1 and List2 before swap\n");

printf("\nList 1:");
for (i = 0; i < 5; i++)
{
    printf("\t%d", List1[i]);
}

printf("\nList 2:");

for (j = 0; j < 5; j++)//removed the semicolon here
{
    printf("\t%d", List2[j]);
}

for(i = 0; i < 5; i++)
{
    temp = List1[i];
    List1[i] = List2[i];
    List2[i] = temp;
}

 //??? put something here to swap the elements and 

printf("\nList1 and List2 after swap");
printf("\nList 1:");
for (i = 0; i < 5; i++)
{
    printf("\t%d", List1[i]);
}

printf("\nList 2:");

for (j = 0; j < 5; j++)//removed the semicolon here
{
    printf("\t%d", List2[j]);
}
return 0;
}

这将导致输出如下：

> Please enter the values to List1 array   

>1 2 3 4 5 

>Please enter the values to List2 array

>9 8 7 6 5 
>
>List1 and List2 before swap
> 
> List 1: 1   2   3   4   5 

>List 2:  9   8   7   6   5 

>List1 and List2 after swap 

>List 1:  9   8   7   6   5 

>List 2:  1   2   3   4   5

希望这对您有帮助！

C程序输出数组列表，然后在列表之间交换元素并再次输出

2 个答案: