“数字”类型不能分配给“字符串”类型

时间:2018-10-03 04:08:56

标签: angular sweetalert2

我有一个错误:

  

“数字”类型不能分配给“字符串”类型。

此位置有错误:

swal.getContent().querySelector('strong').textContent = swal.getTimerLeft()

我该如何解决?

完整代码:

    let timerInterval
    swal({
      title: 'Auto close alert!',
      html: 'I will close in <strong></strong> seconds.',
      timer: 2000,
      onOpen: () => {
        swal.showLoading()
        timerInterval = setInterval(() => {
          swal.getContent().querySelector('strong')
            .textContent = swal.getTimerLeft()
        }, 100)
      },
      onClose: () => {
        clearInterval(timerInterval)
      }
    }).then((result) => {
      if (
        // Read more about handling dismissals
        result.dismiss === swal.DismissReason.timer
      ) {
        console.log('I was closed by the timer')
      }
    })

1 个答案:

答案 0 :(得分:3)

Node.textContent是字符串,而swal.getTimerLeft()不返回字符串。

要解决此问题,请使用Number.prototype.toString()

swal.getContent().querySelector('strong').textContent = swal.getTimerLeft().toString();