Question

我正在使用ruby，并使用了一个名为 food2fork.com 的API。我有两个文件 recipes_controller.rb和recipes.rb

#recipes.rb

require 'httparty'

class Recipe
  include HTTParty 

  default_options.update(verify: false)
  base_uri "http://food2fork.com/api"
  default_params  key: ENV["FOOD2FORK_KEY"]
  format :json

  def self.for (para)
    get("/search",query: {q:para})["recipes"]
  end
end

和第二个文件recipes_controller.rb

require_relative 'recipes'
puts Recipe.for("chocolate")

但是当我在命令行中运行recipes_controller.rb文件时，出现错误

    `
  C:\Users\Hamza\module-3-assignment-1>ruby recipes_controller.rb
  C:/RailsInstaller/Ruby2.3.3/lib/ruby/2.3.0/json/common.rb:156:in `parse': 
  822: unexpected token at 'FORBIDDEN' (JSON::ParserError)
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/2.3.0/json/common.rb:156:in ` 
   parse'
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/gems/2.3.0/gems/httparty- 
    0.16.2/lib/httparty/parser.rb:125:in `json'
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/gems/2.3.0/gems/httparty- 
    0.16.2/lib/httparty/parser.rb:145:in `parse_supported_format'
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/gems/2.3.0/gems/httparty- 
   0.16.2/lib/httparty/parser.rb:110:in `parse'
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/gems/2.3.0/gems/httparty- 
   0.16.2/lib/httparty/parser.rb:69:in `call'
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/gems/2.3.0/gems/httparty- 
   0.16.2/lib/httparty/request.rb:391:in `parse_response'
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/gems/2.3.0/gems/httparty- 
    0.16.2/lib/httparty/request.rb:359:in `block in handle_response'
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/gems/2.3.0/gems/httparty- 
    0.16.2/lib/httparty/response.rb:25:in `parsed_response'
    from C:/RailsInstaller/Ruby2.3.3/lib/ruby/gems/2.3.0/gems/httparty- 
   0.16.2/lib/httparty/response.rb:96:in `method_missing'
    from C:/Users/Hamza/module-3-assignment-1/receipes.rb:12:in `for'
    from recipes_controller.rb:4:in `<main>'

Answer 1

您似乎发送了错误的api密钥

尝试这样做：

qp.And(cbft.NewConjunctionQuery( cbft.NewMatchQuery("Available").Field("status") ))

没有得到具体的答案

1 个答案: