在使用withLatestFrom时,我正在努力将参数传递给选择器,这是从加载动作有效负载中较早映射的
loadLocalSubServices$: Observable<Action> = this.actions$.pipe(
ofType(LocalSubServiceTemplateActions.LocalSubServicesTemplateActionTypes.LoadLocalSubService),
map((action: LocalSubServiceTemplateActions.LoadLocalSubService) => action.payload.globalSubServiceId),
// and below I would like to pass globalSubServiceId
withLatestFrom(this.store.pipe(select(fromLocalSubservices.getSearchParams(globalSubServiceId)))),
map(searchParams => searchParams[1]),
mergeMap((params) =>
this.subServiceService.getLocalSubServices(params).pipe(
map(localSubServices => (new LocalSubServiceTemplateActions.LocalSubServiceLoadSuccess(localSubServices))),
catchError(err => of(new LocalSubServiceTemplateActions.LocalSubServiceLoadFail(err)))
)
)
);
答案 0 :(得分:4)
我想我有您(或未来的流浪者)想要的食谱。您必须将初始有效负载(下面的of
运算符)映射到内部可观察对象,以便可以通过管道将其作为参数传递给withLatestFrom
。然后mergeMap
将其展平,您可以将其作为一个数组返回给下一个运算符,并以初始有效载荷作为第一个值。
map(action => action.payload),
mergeMap(id) =>
of(id).pipe(
withLatestFrom(
this.store.pipe(select(state => getEntityById(state, id))),
this.store.pipe(select(state => getWhateverElse(state)))
)
),
(id, latestStoreData) => latestStoreData
),
switchMap(([id, entity, whateverElse]) => callService(entity))
答案 1 :(得分:1)
您应该能够使用箭头功能。
loadLocalSubServices$: Observable<Action> = this.actions$.pipe(
ofType(LocalSubServiceTemplateActions.LocalSubServicesTemplateActionTypes.LoadLocalSubService),
map((action: LocalSubServiceTemplateActions.LoadLocalSubService) => action.payload.globalSubServiceId),
(globalSubServiceId) => {
return withLatestFrom(this.store.pipe(select(fromLocalSubservices.getSearchParams(globalSubServiceId))));
},
map(searchParams => searchParams[1]),
mergeMap((params) =>
this.subServiceService.getLocalSubServices(params).pipe(
map(localSubServices => (new LocalSubServiceTemplateActions.LocalSubServiceLoadSuccess(localSubServices))),
catchError(err => of(new LocalSubServiceTemplateActions.LocalSubServiceLoadFail(err)))
)
)
);