Question

对于下面的这些查询，

/*----------------------------------------------------Update temporary-----------------------------------------------------------------*/
$con = new mysqli('localhost','aaa','bbb','db');

$sql1 = $con->prepare("	UPDATE temporary 	SET status = 1 WHERE 	cat_no 	= ? AND po_no = ?");
$sql1->bind_param('ss', $cat_no, $po_no);
$sql1->execute(); 
/*----------------------------------------------------Update products-------------------------------------------------------------*/
$sql2 = $con->prepare("	UPDATE products 	SET qty = ? WHERE 	cat_no 	= ? ");
$sql2->bind_param("ss", $qty, $cat_no);
$sql2->execute(); 

mysqli_close($con);

如何编写交易，以便：

1）如果任何一条语句执行失败，它将回滚到原始状态。

2）两个语句都成功执行，然后提交。

任何人都可以帮忙吗？

Answer 1

尝试这样的事情：

try
{
  $conn = new PDO("mysql:host=localhost;dbname=db","aaa","bbb");
  $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
}
catch(PDOException $e)
{
  echo "Could not acquire database handle: ".$e->getMessage(); 
}

$stm1 = $conn->prepare("UPDATE temporary SET status = 1 WHERE cat_no = ? AND po_no = ?");
$stm2 = $conn->prepare("UPDATE products SET qty = ? WHERE cat_no = ?");

$conn->beginTransaction();
try
{
  $stm1->execute(array($cat_no, $po_no));
  $stm2->execute(array($qty, $cat_no));
  $conn->commit();
}
catch (PDOException $e)
{
  $conn->rollBack();
  echo "SQL error = ".$e->getMessage();
}

如何为2个准备好的语句编写事务以确保提交或回滚

1 个答案: