<!DOCTYPE html>
<html lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>MyInformation</title>
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>
<p id = "p1">This is paragraph 1</p>
<p id = "p2">This is paragraph 2</p>
<p id = "p3">This is paragraph 3</p>
<script>
$(p1).on
({
mouseenter: function ()
{
$(this).css("color","red");
},
mouseleave: function () {
$(this).css("color","black");
}
click: function () {
alert("hello");
}
});
</script>
</body>
</html>
答案 0 :(得分:1)
您的选择器错误,语法有些错误,这是固定版本:
<!DOCTYPE html>
<html lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>MyInformation</title>
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>
<p id = "p1">This is paragraph 1</p>
<p id = "p2">This is paragraph 2</p>
<p id = "p3">This is paragraph 3</p>
<script>
$('#p1').on
({
mouseenter: function () {
$(this).css("color","red");
},
mouseleave: function () {
$(this).css("color","black");
},
click: function () {
alert("hello");
}
});
</script>
</body>
</html>
答案 1 :(得分:0)
在df1 = df.groupby([pd.Grouper(freq='1D'), 'A']).size().unstack(fill_value=0)
#alternative
#df1 = df.groupby(pd.Grouper(freq='1D'))['A'].value_counts().unstack(fill_value=0)
df1['new'] = df1['Passed'].div(df1.sum(axis=1))
#alternative
#df1['new'] = df1['Passed'].div(df1['Passed'].add(df1['Failed']))
print (df1)
A Failed Passed new
2018-01-01 5 3 0.375
2018-01-02 5 3 0.375
2018-01-03 4 4 0.500
2018-01-04 4 4 0.500
2018-01-05 4 4 0.500
2018-01-06 3 5 0.625
2018-01-07 4 4 0.500
2018-01-08 5 3 0.375
2018-01-09 4 4 0.500
2018-01-10 4 4 0.500
2018-01-11 4 4 0.500
2018-01-12 7 1 0.125
2018-01-13 0 4 1.000
函数之后您错过了逗号
mouseleave
答案 2 :(得分:0)
您的代码中有两个错误
$(p1)
应该是$('#p1')
mouseleave 功能后缺少逗号
mouseleave: function () {
$(this).css("color","black");
},
click: function () {
alert("hello");
}